Hi there!
I. Only momentum is conserved.
An inelastic collision means that there is a LOSS in the KINETIC ENERGY of the system.
However, momentum is ALWAYS conserved for every type of collision unless there is an external force acting on the system.
Answer:

Explanation:
To answer the question, we just need to consider the motion along the horizontal direction.
The component of the initial velocity of the ice skater along the x-direction is:

where u = 2.25 m/s is the initial velocity and
is the angle.
The component of the final velocity of the ice skater along the x-direction is

where u = 4.65 m/s is the final velocity and
is the angle.
The acceleration along the x-direction is given by

where
t = 120 s is the time
Substituting,

It will move in the direction you pushed it, but it will go at a certain velocity
Answer:
823.46 kgm/s
Explanation:
At 9 m above the water before he jumps, Henri LaMothe has a potential energy change, mgh which equals his kinetic energy 1/2mv² just as he reaches the surface of the water.
So, mgh = 1/2mv²
From here, his velocity just as he reaches the surface of the water is
v = √2gh
h = 9 m and g = 9.8 m/s²
v = √(2 × 9 × 9.8) m/s
v = √176.4 m/s
v₁ = 13.28 m/s
So his velocity just as he reaches the surface of the water is 13.28 m/s.
Now he dives into 32 cm = 0.32 m of water and stops so his final velocity v₂ = 0.
So, if we take the upward direction as positive, his initial momentum at the surface of the water is p₁ = -mv₁. His final momentum is p₂ = mv₂.
His momentum change or impulse, J = p₂ - p₁ = mv₂ - (-mv₁) = mv₂ + mv₁. Since m = Henri LaMothe's mass = 62 kg,
J = (62 × 0 + 62 × 13.28) kgm/s = 0 + 823.46 kgm/s = 823.46 kgm/s
So the magnitude of the impulse J of the water on him is 823.46 kgm/s