Answer:
Wf = –750J
Explanation:
The full solution can be found in the attachment below.
This problem involves the concepts of conservation of momentum and energy.
The potential energy of the sled and child combined is constant since thehy are moving in a level surface.
To find the initial velocity of the sled with child we use the principle of momentum conservation to calculate the v1 which is the commovelocity of the child and sled.
The gravitational potential energy is 25.6 J
Explanation:
The gravitational potential energy (GPE) of an object is given by:
where
m is the mass of the object
g is the gravitational field strength
h is the height of the object above the ground
In this problem, we have
m = 8 kg is the mass of the brick
g = 1.6 N/kg is the gravitational field strength on the moon
h = 2 m is the height of the brick above the ground
Substituting,
Learn more about gravitational potential energy:
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Answer:
F= 224 N
Explanation:
Given that
mass ,m = 80 kg
Radius ,r= 5 m
speed at the top v= 8 m/s
The force at the top = F
Now by using the Second law of Newton's
Now by putting the values
Take g = 10 m/s²
F= 224 N
Therefore the force exerted by the track at the top position will be 224 N.
Solution :
The angular acceleration, is obtained from the equation of the
of rotational motion,
Thus,
or
where is torque, F is force, d is moment arm distance, I is the moment of inertia
Thus,
Now if the force and the moment arm distance are constant, then the
That is when, F = d = constant, then .
Thus, moment of inertia, I is proportional to mass of the bar.
The mass is less for the bar in case (1) in comparison with that with the bar in case (2) due to the holes that is made in the bar.
Therefore, the bar in case (1), has less moment of inertia and a greater angular acceleration.
ITs CGS unit.
Hence