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Vika [28.1K]
3 years ago
7

A car moves from the point (3.0 m)x^ + (5.0 m)y^ to the point (8.0 m)x^ - (7.0 m)y^ in 2.0 s. what is the magnitude of the avera

ge velocity of the car?
Physics
1 answer:
Mandarinka [93]3 years ago
4 0
8.0-3.0=5.0metres in the x direction
7.0-5.0=2.0 metres in the y direction
Use Pythagoras
25+4=29
\sqrt[2]{29  }
=5.39metres in 2secs
=2.645m/s at an angle of 68.2 degrees to horizontal.... see below!
tan-1 angle = 5/2
angle=68.2 degrees
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Here we have a simple matter of conservation of energy. ME=PE+KE.

At point A we have PE=mgh and KE=1/2mv^2. At point A all we have is PE since the coaster isn’t rolling yet. But by conservation of energy, we know that it will have enough energy to roll down and get to and equal height on another hill. Providing we are neglecting friction and drag and resistance forces which we are in this case. So we can conclude that the KE will be greater at Point B since ME=PE+KE and for ME to remain the same and we know the PE is less on lower hill, so we can conclude that KE on lower hill is greater to keep ME the same and have conservation of energy.

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Explanation:

Given parameters:

Mass of Neil Armstrong = 160kg

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The weight of Armstrong on earth is 1328N more than on the moon.

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Weight and mass brainly.com/question/5956881

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