Question

A car moves from the point (3.0 m)x^ + (5.0 m)y^ to the point (8.0 m)x^ - (7.0 m)y^ in 2.0 s. what is the magnitude of the average velocity of the car?

Answer 1

8.0-3.0=5.0metres in the x direction
7.0-5.0=2.0 metres in the y direction
Use Pythagoras
25+4=29
$\sqrt[2]{29 }$
=5.39metres in 2secs
=2.645m/s at an angle of 68.2 degrees to horizontal.... see below!
tan-1 angle = 5/2
angle=68.2 degrees