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MAVERICK [17]
1 year ago
13

which planet detection method would work best for a massive planet that's close to its host star but doesn't pass between us and

the star?
Physics
1 answer:
Alona [7]1 year ago
3 0

The Doppler method is most frequently employed to find extrasolar planets, however it works best for finding extremely large planets that are near to their host star.

<h3>Which planet is the hottest?</h3>

Venus is the hottest planet within our solar system, with average global temperatures hot enough even to melt lead due to the runaway greenhouse effect caused by its thick atmosphere, which traps heat. Venus is around 700°F (390°C) hotter that it would be in the absence of the greenhouse effect.

<h3>Is it 8 or 9 planets?</h3>

Our solar system is made up of ten planetary systems, 146 moons, countless comets, meteorites, and other space objects, as well as Pluto and several dwarf planets. In the system, there is just the Sun. The eight planets are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and finally Neptune.

To know more about planet visit:

brainly.com/question/15268075

#SPJ4

You might be interested in
If a 75 W lightbulb is 15% efficient, how many joules of light energy does the bulb produce every minute?
stiks02 [169]

Answer:

1 W = 1 J / sec       Definition of watt is 1 joule / sec

So if a bulb uses 75 J / sec it must use

75 J/s * 60 sec / min = 4500 J/min    energy used by bulb

If bulb is 15% efficient then the light delivered is

P = 4500 J / min * .15 = 675 J / min

4 0
3 years ago
Write down short notes on:<br>a. Electrical energy​
PilotLPTM [1.2K]

Answer:

Explanation:

Electrical energy is energy derived from electric potential energy or kinetic energy.

Or,

Electrical energy is a form of energy resulting from the flow of electric charge. Lightning, batteries and even electric eels are examples of electrical energy.People use electricity for lighting, heating, cooling, and refrigeration and for operating appliances, computers, electronics, machinery, and public transportation systems.

Hope it helped you.

4 0
2 years ago
On a trip to the Colorado Rockies, you notice that when the freeway goes steeply down a hill, there are emergency exits every fe
Zanzabum

Answer:

The maximum speed that the truck can have and still be stopped by the 100m road is the speed that it can go and be stopped at exactly 100m. Since there is no friction, this problem is similar to a projectile problem. You can think of the problem as being a ball tossed into the air except here you know the highest point and you are looking for the initial velocity needed to reach that point. Also, in this problem, because there is an incline, the value of the acceleration due to gravity is not simply g; it is the component of gravity acting parallel to the incline. Since we are working parallel to the plane, also keep in mind that the highest point is given in the problem as 100m. Solving for the initial velocity needed to have the truck stop after 100m, you should find that the maximum velocity the truck can have and be stopped by the road is 18.5 m/s.

Explanation:

4 0
3 years ago
What is the relationship between Newton's first law of motion and inertia?​
adelina 88 [10]

Explanation: Newton's first law of motion states that a body at rest remains at rest, or, if in motion, remains in motion at a constant velocity unless acted on by a net external force. This is also known as the law of inertia. Inertia is the tendency of an object to remain at rest or remain in motion.

4 0
3 years ago
A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and
Paladinen [302]
Answer: Option B.

Since here the truck is moving on a circular track, it will experience centripetal force.

F(centripetal) = m × acc 
or 
r = \frac{m v^{2}}{F}

where r is the radius of the track. 
m is the mass of truck
v is the speed  of the truck. 
Given: v = <span>13 m/s
m = </span><span>1,600 kg
</span>F = 3300 Newton

To find = radius of track=?
r = \frac{m v^{2} }{F}
r = \frac{1600*13*13}{3300}
r = 81.94 m
Therefore, radius of track is 81.94 m
4 0
3 years ago
Read 2 more answers
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