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MAVERICK [17]
1 year ago
13

which planet detection method would work best for a massive planet that's close to its host star but doesn't pass between us and

the star?
Physics
1 answer:
Alona [7]1 year ago
3 0

The Doppler method is most frequently employed to find extrasolar planets, however it works best for finding extremely large planets that are near to their host star.

<h3>Which planet is the hottest?</h3>

Venus is the hottest planet within our solar system, with average global temperatures hot enough even to melt lead due to the runaway greenhouse effect caused by its thick atmosphere, which traps heat. Venus is around 700°F (390°C) hotter that it would be in the absence of the greenhouse effect.

<h3>Is it 8 or 9 planets?</h3>

Our solar system is made up of ten planetary systems, 146 moons, countless comets, meteorites, and other space objects, as well as Pluto and several dwarf planets. In the system, there is just the Sun. The eight planets are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and finally Neptune.

To know more about planet visit:

brainly.com/question/15268075

#SPJ4

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A rifle of mass 2 kg is suspended by strings. The rifle fires a bullet of mass 0.01 kg at a speed of 200 m/s. The recoil velocit
ozzi

Answer:

option D  

Explanation:

given,

mass of the rifle,M = 2 Kg

mass of the bullet , m = 0.01 Kg

speed of the bullet, v = 200 m/s

recoil velocity ,v'= ?

initial velocity of bullet and rifle is zero.

using conservation of energy

Mu + m u' = M v'+ m v

0 + 0  = 2 x v' + 0.01 x 200

2 v' = -2

   v' = -1 m/s

negative sign represent the velocity of rifle is in opposite direction of bullet.

hence, the correct answer is option D  

5 0
3 years ago
Corey runs a 100-meter race. 7 seconds after the race started Corey is 45 meters from the starting line and reaches his max spee
RUDIKE [14]

Answer:

  • Corey's max speed is 7 \frac{m}{s}
  • the distance Corey's covers in z seconds is 7 \frac{m}{s} * z \ s
  • d (z) = 45 m + 7 \frac{m}{s} * z
  • d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

Explanation:

<h3>Corey's max speed</h3>

For constant speed, we know:

v=\frac{distance}{time}

The distance between the 80 meters and the 45 meters is:

distance = 80 m - 45 m = 35 m

and the time it took to reach the 80 meter will be:

time = 12 s - 7 s = 5 s

So, Corey's max speed is

v_{max}=\frac{35 m}{5 s} = 7 \frac{m}{s}

<h3>How far runs Corey</h3>

As the velocity of Corey's is v_{max}, the distance Corey's covers in z seconds is

distance = v_{max} * z \ s

distance = 7 \frac{m}{s} * z \ s

<h3>What is Corey's distance from the starting line</h3>

At time 7 + z seconds the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (z) = 45 m + v_{max} * z

d (z) = 45 m +7 \frac{m}{s} * z

At time x ( x greater or equal to 7 seconds) the distance will be the 45 meters he covers in the first part of the race plus the distance he traveled at constant speed. this is:

d (x) = 45 m + v_{max} * (x-7 s)

d (x) = 45 m + 7 \frac{m}{s} * (x-7 s)

4 0
3 years ago
If you were to take the universe's temperature, what would the reading be?
Fiesta28 [93]
I think the correct answer choice is c
6 0
3 years ago
If 27 J of work are needed to stretch a spring from 15 cm to 21 cm and 45 J are needed to stretch it from 21 cm to 27 cm, what i
kupik [55]

Answer:

9 cm.

Explanation:

The energy used for stretch the spring from 15 cm to 21 cm will be , E_{1}=27J

The energy used for stretch the spring from 21 cm to 27 cm will be , E_{2}=45J

using the energy of spring formula ,we find that

27 = \frac{1}{2}K((21-L^{2})-(15-L^{2}))

45 = \frac{1}{2}K((27-L^{2})-(21-L^{2}))

Dividing both the equation will get,

\frac{3}{5}=\frac{(21-L)^{2}-(15-L)^{2}}{(27-L)^{2}-(21-L)^{2}}\\5((21-L)^{2}-(15-L)^{2})=3((27-L)^{2}-(21-L)^{2})\\3(729 - 54L + L^{2}- 441 + 42L - L^{2} ) = 5(441 - 42L + L^{2} - 225 + 30L - L^{2} )\\3(288 - 12L) = 5(216 - 12L)\\24L = 216\\L = 9 cm

Therefore, the natural length of the spring is, 9 cm.

4 0
3 years ago
You skip north for 12 minutes to your best friend's house that is 1.5 kilometers away. What is your average velocity?
bagirrra123 [75]

Answer:

The average velocity is 7.5 km/h

Explanation:

Let's convert minutes to hours so our answer can be given in a common units of km/hour:

12 minutes = 12/60  hours = 0.2 hours

Now we estimate the average velocity calculating the distance travelled over the time it took:

1.5 / 0.2 km/h = 7.5 km/h

3 0
3 years ago
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