Answer:
net force acting on the floor is 100 kN
Explanation:
Given data:
dimension of floor = 2 m \times 0.5 m
we know that
Net force can be calculated as follow
Therefore net force acting on the floor is 100 kN
Answer:
kjeo;fwigyds79ay08u-9[onpuefi2 ugw]yw=i\-o3ef
pw]oe;iLH[U
I\EF]
';/ilewuf[p';w iflkh;pif;oewu hf;wfyw hfu we
Explanation:
Answer:
try to pop it back in good luck im scared for you
Positive integer n design an algorithm
Answer:
All 3 principal stress
1. 56.301mpa
2. 28.07mpa
3. 0mpa
Maximum shear stress = 14.116mpa
Explanation:
di = 75 = 0.075
wall thickness = 0.1 = 0.0001
internal pressure pi = 150 kpa = 150 x 10³
torque t = 100 Nm
finding all values
∂1 = 150x10³x0.075/2x0,0001
= 0.5625 = 56.25mpa
∂2 = 150x10³x75/4x0.1
= 28.12mpa
T = 16x100/(πx75x10³)²
∂1,2 = 1/2[(56.25+28.12) ± √(56.25-28.12)² + 4(1.207)²]
= 1/2[84.37±√791.2969+5.827396]
= 1/2[84.37±28.33]
∂1 = 1/2[84.37+28.33]
= 56.301mpa
∂2 = 1/2[84.37-28.33]
= 28.07mpa
This is a 2 d diagram donut is analyzed in 2 direction.
So ∂3 = 0mpa
∂max = 56.301-28.07/2
= 14.116mpa
