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Alekssandra [29.7K]
4 years ago
14

A microphone is attaced to a spring that is suspended from

Physics
1 answer:
kirill115 [55]4 years ago
3 0

To solve this problem we will apply the concept related to the amplitude and the Doppler effect. The difference between the maximum and minimum frequency detected by the microphone would be given by the mathematical function

f_{max} - f_{min} = 2 f_s (\frac{v_0}{v})

Here,

f_s= Source Frequency

v_0 = Speed of microphone

v = Speed sound

f_{max} - f_{min} = 2 f_s (\frac{v_0}{v})

Maximum speed of the microphone is

v_0 = f_{max} - f_{min} * \frac{v}{2f_s}

v_0= \frac{2.1Hz*343m/s}{2*440Hz}

v_0= 0.8185 m/s

Now the amplitude is

A = \frac{v_0}{2\pi/T}

Here T means the Period, then

A= \frac{0.8185 * 2.0}{2\pi}

A= 0.2605m

Therefore the amplitude of the simple harmonic motion is 0.2605m

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he membrane that surrounds a certain type of living cell has a surface area of 6.0 x 10-9 m2 and a thickness of 1.6 x 10-8 m. As
k0ka [10]

Answer:

1.54481175\times 10^{-12}\ C

Explanation:

\epsilon_0 = Permittivity of free space = 8.85\times 10^{-12}\ F/m

A = Area = 6\times 10^{-9}\ m^2

d = Thickness = 1.6\times 10^{-8}\ m

k = Dielectric constant = 5.4

V = Voltage = 86.2 mV

Charge is given by

Q=CV\\\Rightarrow Q=k\epsilon\dfrac{A}{d}V\\\Rightarrow Q=5.4\times 8.85\times 10^{-12}\times \dfrac{6\times 10^{-9}}{1.6\times 10^{-8}}\times 86.2\times 10^{-3}\\\Rightarrow Q=1.54481175\times 10^{-12}\ C

The charge on the outer surface is 1.54481175\times 10^{-12}\ C

4 0
3 years ago
A scientist uses a camera to study the stars.
likoan [24]

Answer:

All of teh above except A

Explanation:

3 0
3 years ago
A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope
serious [3.7K]
<span>A 67.0 kg crate is being raised by means of a rope. Its upward acceleration is 3.50 m/s2. What is the force exerted by the rope on the crate? 

</span>Newton's Second Law<span> of Motion states, “The force acting on an object is equal to the mass of that object times its acceleration.” We calculate as follows:
</span>
F = ma = 67.0 kg (3.50 m/s^2) = 234.5 J
7 0
3 years ago
What is the speed of a beam of electrons when under the simultaneous influence of E = 1.64×104 V/m B = 4.60×10−3 T Both fields a
andrezito [222]

Answer: v = 3.57×10^6 m/s; R = 4.42×10^-3m; T = 7.78×10^-9 s

Explanation:

Magnetic force(B) = 4.60×10^-3 T

Electric force(E) = 1.64×10^4 V/m

Both forces having equal magnitude ;

Magnetic force = electric force

qvB = qE

vB = E

v = (1.64×10^4) ÷ (4.60×10^-3)

v = 3.57×10^6 m/s

2.) Assume no electric field

qvB = ma

Where a = v^2 ÷ r

R = radius

a = acceleration

v = velocity

qvB = m(v^2 ÷ R)

R = (m×v) ÷ (|q|×B)

q=1.6×10^-19C

m = 9.11×10^-31kg

R = (9.11×10^-31 * 3.57×10^6) ÷ (1.6×10^-19 * 4.6×10^-3)

R = 32.5227×10^-25 ÷ 7.36×10^-22

R = 4.42×10^-3m

3.) period(T)

T = (2*pi*R) ÷ v

T = (2* 4.42×10^-3 * 3.142) ÷ (3.57×10^6)

T = (27.775×10^-3) ÷(3.57×10^6)

T = 7.78×10^-9 s

6 0
4 years ago
Once ignited, a small rocket motor on a spacecraft exerts a constant force of 10 N for 7.80s. During the burn the rocket causes
Marat540 [252]

Answer:

a = 0.01 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which says that the sum of forces on a body is equal to the product of mass by acceleration.

ΣF = m*a

where:

F = forces = 10 [N]

m = mass = 100 [kg]

a = acceleration [m/s²]

10 = 100*a

a = 0.01 [m/s²]

4 0
4 years ago
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