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Shtirlitz [24]
3 years ago
13

The formula for the area of a rhombus with diagonals of lengths c and

Mathematics
2 answers:
Irina18 [472]3 years ago
7 0

Answer: part a.) c =2A/d

Part b.) d = 7

Part C The diagonals are each 8

Step-by-step explanation: part b:

35= 10d/2 70= 10d. 7 =d

Part c 32= 2c²

64 = c²

√64 = √c²

c = 8

Amiraneli [1.4K]3 years ago
5 0
The answer is part a
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Taya2010 [7]

Answer:

<u>12in long</u> and <u>10in wide</u>

Step-by-step explanation:

If he were to trim the edges of the photographs to 12\frac{1}{2} and 10\frac{1}{2}, the edges of the photographs from Russ's vacation would be too long and wide to fit inside of the photo album.

If you convert the fractions into decimals, you can easily discern that the vacation photos would be too large to fit inside of the photo album.

Photo Album:

12\frac{1}{8} = 12.1 inches •Original

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12\frac{1}{2} = 12.5 inches > 12.1 - 12.5 = -0.4 •Too large

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8 0
3 years ago
What is partial derivative of z=(2x+3y)^10 with respect to x,y?
maw [93]
Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9

\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9

Or, if you actually did want the second order derivative,

\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8

and in case you meant the other way around, no need to compute that, as z_{xy}=z_{yx} by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because z is a polynomial).
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3 years ago
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Answer:

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Think of it like this.

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Vera_Pavlovna [14]

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