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3 years ago

In order for the bug to fly through the air a force has to push the bug forward. Identify this force. How does the bug produce

1 answer:

5 0

While a bug fly in the air the weight of bug is counter balanced by the buoyancy force that is applied by air on the bug

This buoyancy force is net upthrust on the bug due to air which will help the bug to float in the air

This buoyancy force is given by the formula

$F_b = \rho V g$

here we know that

$\rho$ = density of air

V = volume of bug

so here we can say that upthrust of air is the force that bug will experience during his uplift

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4 years ago

A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.

Vlad1618 [11]

Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.
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t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²

Answer: 44.7 m/s²

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antiseptic1488 [7]

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3 years ago

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A spherical hot-air balloon is initially filled with air at 120 kPa and 20°C with an initial diameter of 5 m. Air enters this ba

GrogVix [38]

Answer:

27.78 s

Explanation:

Assume ideal gas, since pressure and temperature of the air inside the balloon is the same as air entering the balloon, then the volume (and its rate) stays the same.

The cross-sectional area of the hole where air enters

$A = \pi d^2/4 = \pi 1^2/4 = \pi/4 m^2$

Hence the volume rate:

$\dot{V} = vA = 3*\pi/4 = 3\pi/4 m^3/s$

The total volume of the spherical balloon is

$V = 4\pi r^3/3 = 4\pi (5/2)^3/3 = 125\pi/6 m^3$

Hence the time it takes to fill this much at a constant rate of 3π/4 is

$t = V/\dot{V} = \frac{125\pi/6}{3\pi/4} = \frac{125*4}{6*3} = 27.78 s$

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3 years ago