Answer:
Correct answer: p₂ : p₁ = 1 : 3
Explanation:
A process that occurs at a constant temperature is called an isothermal process and the formula that applies to this process is:
p · V = const where p is pressure and V is volume
Given : V₂ = 3 V₁
p₁ V₁ = p₂ V₂ ⇒ p₂ / p₁ = V₁ / V₂ ⇒ p₂ / p₁ = V₁ / 3 V₁ ⇒ p₂ / p₁ = 1 / 3
p₂ : p₁ = 1 : 3
which means that when the volume is increased three times the pressure is reduced three times
God is with you!!!
the answer to your question is physical fitness
Answer:
Part a)
P = 13.93 kW
Part b)
R = 8357.6 Cents
Explanation:
Part A)
heat required to melt the aluminium is given by

here we have



Since this is the amount of aluminium per hour
so power required to melt is given by



Since the efficiency is 85% so actual power required will be

Part B)
Total energy consumed by the furnace for 30 hours



now the total cost of energy consumption is given as


