To solve this problem we will apply the concepts related to the linear kinematic movement. We will start by finding the speed of the body from time and the acceleration given.
Through the position equations we will calculate the distance traveled.
Finally, using this same position relationship and considering the previously found speed, we can determine the time to reach your goal.
For time (t) and acceleration (a) we have to,
The velocity would be,
Now the position is,
Now with the initial speed and position found we will have the time is,
Solving the polynomian we have,
Therefore the rocket will take to hit the ground around to 4.56min
Explanation:
Acceleration of an object is calculated by finding the change in its velocity divided by time taken.
If 
is initial velocity, 
is final velocity and t is time taken. Then the acceleration of the object is given by :
.....(1)
So, the above equation is used to find acceleration. It is called the first equation of motion. After rearranging equation (1), the correct options are :
Answer:
Friction is the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other. There are several types of friction: Dry friction is a force that opposes the relative lateral motion of two solid surfaces in contact.
Coefficient of friction, ratio of the frictional force resisting the motion of two surfaces in contact to the normal force pressing the two surfaces together. It is usually symbolized by the Greek letter mu (μ). Mathematically, μ = F/N, where F is the frictional force and N is the normal force.
The magnitude of a point charge is 0.189 x 10⁻⁹C.
<h3>Steps</h3>
We have stated that the point charge's electric field is E=2.5 N/C.
Distance from point charge R = 51 cm = 0.51 m
We are aware that the electric field resulting from a point charge is given as E = 1 / 4π∈₀ × Q / R²
so 2.5 = 9 x 10⁹ Q/ 0.68²
The magnitude of a point charge is 0.189 x 10⁻⁹C.
The electric force per unit charge is referred to as the electric field. It is assumed that the field's direction corresponds to the force it would apply to a positive test charge.
From a positive point charge, the electric field radiates outward, and from a negative point charge, it radiates in.
learn more about electric field here
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