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Fantom [35]
3 years ago
7

In a parallel circuit, if one connection is broken

Physics
1 answer:
nirvana33 [79]3 years ago
7 0
C hope that helps hens
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How much heat would be needed to completely evaporate 31.5 g of boiling water at a temperature of 100 "C? Express your answer in
BaLLatris [955]

Answer:

Heat needed = 71.19 J

Explanation:

Here heat required can be calculated by the formula

            H = mL

M is the mass of water and L is the latent heat of vaporization.

Mass of water, m = 31.5 g = 0.0315 kg

Latent heat of vaporization of water = 2260 kJ/kg

Substituting

            H = mL = 0.0315 x 2260 = 71.19 kJ

Heat needed = 71.19 J

7 0
3 years ago
Mary travelled 70 miles/hour due north. This is an example of what?
kolezko [41]
I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.
4 0
2 years ago
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Define wheel and axle 4 example of wheel and axle​
natita [175]

Answer:

A system of two co-axial cylindersof different diameters which rotate together is called wheel and axle example; the door knob , knob of the tap ,screw driver,water tap

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3 years ago
Which is an example of a social network?
GarryVolchara [31]

Answer:

d

Explanation:

4 0
3 years ago
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An object moving due to gravity can be described by the motion equation y=y0+v0t−12gt2, where t is time, y is the height at tha
Lynna [10]

Answer: 6.45 s

Explanation:

We have the following equation:

y=y_{o}+V_{o}t-\frac{1}{2}gt^{2} (1)

Where:

y=0 is the height when the rock hits the ground

y_{o}=75 m the height at the edge of the cilff

V_{o}=20 m/s the initial velocity

g=9.8 m/s^{2} acceleration due gravity

t time

0=75 m+(20 m/s)t-(4.9 m/s^{2})t^{2}  (2)

Rearranging the equation:

-(4.9 m/s^{2})t^{2} + (20 m/s)t + 75 m=0 (3)

At this point we have a quadratic equation of the form at^{2}+bt+c=0, and we have to use the quadratic formula if we want to find  t:

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}  (4)

Where a=-4.9, b=20, c=75

Substituting the known values and choosing the positive result of the equation:

t=\frac{-20\pm\sqrt{20^{2}-4(-4.9)(75)}}{2(-4.9)}  (5)

t=6.453 s  This is the time it takes to the rock to hit the ground

8 0
3 years ago
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