In a parallel circuit, if one connection is broken

WILL MARK BRAINLIEST Why do we see sedimentary rocks more often than igneous and metamorphic rocks?

Arisa [49]

Answer:

because they are the rocks that line the surface of our planet

Explanation:

We see sedimentary rocks more than other rock types because they are the rocks that line the surface of our planet.

Sedimentary rocks typically form the earth cover due to the way they are formed.

These rocks are produced by the weathering, transportation and deposition of sediments within a basin.
In this basin, the sediment is lithified and converted to sedimentary rocks.
These processes are driven by the external heat engine
Therefore, it is confined to the surface.
Igneous and metamorphic rock's processes are confined to the subsurface.

8 0

3 years ago

How are the amplitude and energy of a wave related

In-s [12.5K]

I would go with the last two because they are the same please give me brainiest if i am right

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3 0

3 years ago

Read 2 more answers

1) Si un mango cae a una velocidad de 75m/s y tarda 26 seg. en caer. ¿ Cuál habrá sido la velocidad con qué el mango llegó al su

Lyrx [107]

Answer:

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

Explanation:

El mango experimenta un movimiento de caída libre, es decir, un movimiento uniformemente acelerado debido a la gravedad terrestre, despreciando los efectos de la viscosidad del aire y la rotación planetaria. Entonces, la velocidad final del mango, es decir, la velocidad con la que llega al suelo, se puede determinar mediante la siguiente fórmula cinemática:

$v = v_{o}+g\cdot t$ (1)

Donde:

$v_{o}$ - Velocidad inicial, en metros por segundo.

$v$ - Velocidad final, en metros por segundo.

$g$ - Aceleración gravitacional, en metros por segundo al cuadrado.

$t$ - Tiempo, en segundos.

Si sabemos que $v_{o} = -75\,\frac{m}{s}$ , $g = -9.807\,\frac{m}{s^{2}}$ y $t = 26\,s$ , entonces la velocidad final del mango es:

$v = v_{o}+g\cdot t$

$v = -75\,\frac{m}{s}+\left(-9.807\,\frac{m}{s} \right)\cdot (26\,s)$

$v = -329.982\,\frac{m}{s}$

El mango llega al suelo a una velocidad de 329.982 metros por segundo.

8 0

3 years ago

High speed stroboscopic photographs show that the head of a 244 g golf club is traveling at 57.6 m/s just before it strikes a 45

almond37 [142]

Answer:

The speed will be "1.06 m/s".

Explanation:

The given values are:

Momentum,

m1 = 244 g

m2 = 45.2 g

On applying momentum conservation ,

Let v2 become the final golf's speed.

From Momentum Conservation

⇒ $Total \ initial \ momentum = Total \ final \ momentum$

⇒ $m1\times u1 + m2\times u2 = m1\times v1 + m2\times v2$

On putting the estimated values, we get

⇒ $0.244\times 57.6+0=0.244\times 39.9+45.2\times v2$

⇒ $57.844+0=9.7356+45.2\times v2$

⇒ $48.1084=45.2\times v2$

⇒ $v2=\frac{48.1084}{45.2}$

⇒ $v2=1.06 \ m/s$

6 0

3 years ago

A cylinder with a piston contains 0.250 mol of oxygen at2.40x105 Pa and 355 K. The oxygen may be treated as an ideal gas.The gas

Nikitich [7]

Answer:

= 285 Joules

Explanation:

a) answer can be found out in attachment

(b) The temperature for the isothermal compression is the same as the temp at the end of the isobaric expansion. Since pressure is held constant but volume doubles, we use the ideal gas law:

p V = nR T to see that the temperature also doubles.

.So... temp for isothermal compression = 355×2 = 710 K

.(c) The max pressure occurs at the top point. At this point, the volume is back to the original value but the temperature is twice the original value. So the pressure at this point is twice the original, or

max pressure = 2×240000 Pa = 480000 Pa = 4.80 x 10^5 Pa

(d) total work done by the piston = workdone during isothermal compression - work done during expansion =

= nRT ln(V initial / V final)-p (V initial - V final)

= nRT ln(2) - nR(T final - T initial)

= 0.250× 8.314 ×710×ln(2)-0.250×8.314× (710 - 355)

= 285 Joules

7 0

3 years ago