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soldi70 [24.7K]
3 years ago
10

Write the formula for methionine (red = o, gray = c, blue = n, yellow = s, ivory = h).express your answer as a molecular formula

. enter the elements in the order: c, h, n, o, s.

Chemistry
1 answer:
-BARSIC- [3]3 years ago
3 0

We have to get the formula of methionine.

The formula of methionine is

Methionine is an essential amino acid of human. It is white crystalline solid.

The formula of methionine is C₅H₁₁NO₂S. Methionine contains five carbon atoms, eleven hydrogen atoms, one nitrogen atom, two oxygen atoms and one sulphur atom.

It contains one amino group (-NH₂) and one carboxylic acid group (-COOH). Atoms are depicted in C-atom in grey, H-atom in ivory, O-atom in red, N-atom in blue and S-atom in yellow.

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Why do you think foods and drinks are stored in aluminum cans and not iron cans
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What volume of chlorine gas at 27 °C, 812 mmHg, is required to react with an excess of carbon disulfide so that 5.00kJ of heat i
Kamila [148]

Answer:

The correct answer is 1.21 L.

Explanation:

Based on the given information, the reaction will be,

CS2 (l) + 3Cl2 (g) ⇒ CCl4 (l) + S2Cl2 (l)

By using the standard values of the substances, the standard enthalpy of the reaction is,

ΔH° = [(-139.5) + (-58.5) – 0 – (87.3)] kJ/mol

= -285.3 kJ/mol

The amount of heat evolved for 3 moles of chlorine reacted us 285.3 kJ.

Now the number of moles of chlorine needed to react to produce 5.00 kJ is,

= 5.00 kJ × 3 mol Cl2/285.3 kJ

= 0.0526 mol Cl2

Now the volume of chlorine gas at 27degree C and 812 mmHg will be,

Volume = 0.0526 mol Cl2 × 0.0821 Latm/mol K × 300 K/ 1.07 atm

= 1.21 L

4 0
3 years ago
Volume is a measurement of how fast particles of a substance are moving.
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3 years ago
SYNTHESIS OFCARBONATECTIONLABORATORY SIMULATIONLab Data- X99.00.10CollectedVolume sodium carbonate (mL)Molarity sodium carbonate
evablogger [386]

Answer:

\begin{gathered} \text{Limiting Reagent = Sodium Carbonate} \\ \text{Percent Yield = 98\%} \end{gathered}

Explanation:

The chemical reaction talks about the synthesis of calcium carbonate

It is from the reaction between sodium carbonate and calcium chloride

Let us write the equation of reaction as follows:

Na_2CO_{3(aq)}+CaCl_{2(aq)}\text{ }\rightarrow2NaCl_{(s)\text{ }}+CaCO_{3(aq)}

Firstly, we want to get the expected mass of calcium carbonate

This speaks about getting the theoretical yield based on the equation of reaction

From the data collected, 90 ml of 0.20 M (mol/L) of sodium carbonate gave calcium carbonate

We need to get the actual number of moles of sodium carbonate that reacted

We can get this by multiplying the volume by the molarity (kindly note that we have to convert the volume to Liters by dividing by 1000)

Thus, we have it as:

\frac{90}{1000}\times\text{ 0.1 = 0.009 moles}

Hence, we see that 0.009 moles of sodium carbonate reacted theoretically

Since 1 mole of sodium carbonate gave 1 mole calcium carbonate, it is expected that 0.009 mole of sodium carbonate will give 0.009mole of calcium carbonate

What we have to do now is to get the theoretical grams of calcium carbonate produced

That would be the product of the number of moles of calcium carbonate and its molar mass

The molar mass of calcium carbonate is 100 g/mol

The theoretical yield (expected mass) is thus:

100\text{ g/ mol }\times\text{ 0.009mol = 0.9 g}

Finally, we proceed to get the percentage yield which is calculated using the formula below:

\text{Percent Yield = }\frac{Actual\text{ yield}}{\text{Theoretical yield}}\times\text{ 100 \%}

The actual yield is the observed mass which is given as 0.88 g

The percent yield is thus:

\frac{0.88}{0.9}\times\text{ 100 = }98\text{ \%}

7 0
1 year ago
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