Answer:
2290 steel balls weigh 3,180 grams so each ball weighs 1.3886462882
grams. If you had a 8.87 kilograms of those balls they would number
8,870 grams / 1.3886462882 = 6,388 steel balls
Step-by-step explanation:
Answer:

Step-by-step explanation:

Answer: Choice C) AA similarity
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We are given that angle ABE = angle ECD since they are both right angles (square marker)
Angle AEB = angle CED as they are vertical angles
we have two pairs of congruent angles, leading us to be able to use the AA (angle angle) similarity theorem
Answer:
1 : 1
Step-by-step explanation:
When a circle is inscribed in a cylinder, the height of the cylinder is equal to the diameter of the sphere and the radius of the cylinder is same as that of the sphere.
Let the radius of sphere is r.
height of cylinder, h = 2r
radius of cylinder = r
Surface area of sphere, A = 4πr²
lateral surface area of cylinder, A' = 2 πrh
A' = 2πr x 2r = 4πr²
The ratio of surface area of sphere to the lateral surface area of cylinder is 1 : 1.