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marusya05 [52]
3 years ago
11

If the Moon revolves around the Earth in a circular orbit with a period of 27 days, 7 hours, and 43 minutes, and astronomers hav

e clocked it's orbital speed at 1.03 km/s, what is the centripetal acceleration of the Moon due to its orbit around the Earth?
Physics
1 answer:
inysia [295]3 years ago
6 0

Answer:

T = (27 da * 24 hr/da + 7 hr + 43 min/60 min/hr) * 3600 sec/hr = 2.36 * 10E6 sec       period of moon in sec

C = v t  = 2 pi R        circumference of orbit where v is orbital speed

ac (centripetal acceleration) =  v^2 / R = v^2 / (v t / 2 pi) = 2 pi v / t

ac = 2 pi * 1.03 * 10E3 m/s / 2.36 * 10E6 sec = 2.74 * 10E-3 m /s^2

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How many electrons would have to be removed from one sphere and added to the other to cause an attractive force between the sphe
nasty-shy [4]

Answer:

  # = 6.6 10¹⁵ electrons for r = 1 m

# = 6.6 10¹³ electrons  for r= 1 cm

Explanation:

The electric force is given by Coulomb's law

       F = k q₁ q₂ / r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m²/C², q are the charges and r the distance between them.

Let's apply this equation to our case. Initially the spheres are not attracted so the net charge in each of them is zero, removing electrons in one of them is a positive net charge of equal value to the negative charge removed. The specific answer of this exercise depends on the distance of the two spheres, by calculation we assume that it is 1 m

The charge of an electron is q₀ = -1.6 10⁻¹⁹ C, the total charge is

            q = #_electron  q₀

           F = k # q₀ # q₀ / r²

          #² = F r² / k q₀²

          # = √ F r² / k q₀²

Let's calculate for r = 1 m

         # = √ [1 10⁴ 1 / 8.99 10⁹ (1.6 10⁻¹⁹)²]

         # = √ [43.45 10³⁰]

         # = 6.6 10¹⁵ electrons for r = 1 m

 

If the distance is reduced to r = 1 cm = 1 10⁻² m

The number of electrons is reduced to

         # = 6.6 10¹³ electrons

4 0
4 years ago
During development, the cells in these organisms become specialized.
Y_Kistochka [10]

Answer:

A- multicellular

Explanation:

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7 0
3 years ago
The mass of a basketball is three times greater than the mass of a softball. Compare the momentums of a softball and a basketbal
ki77a [65]

Answer:

The momentum of the basketball is three times that of the softball. Momentum equals mass times velocity. Therefore, if the basketball and softball are moving at the same velocity, and the basketball has three times the mass of the softball, the basketball has three times the momentum of the softball.

Explanation:

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3 years ago
When you take your 1900-kg car out for a spin, you go around a corner of radius 53m with a speed of 13m/s. The coefficient of st
anastassius [24]

Answer:

Ff = 6058.5N

Explanation:

The sum of forces is:

Ff = m*a_c

Ff = m*V^2/R

Ff = 1900*13^2/53

Ff = 6058.5N

3 0
3 years ago
Do heavier objects fall more slowly than lighter objects?
aksik [14]
Think of it like this, gravity has to pull harder on the heavier object to make them fall at the same rate , but doesn't have to pull as hard for the lighter object , thus is why sometimes heavier objects fall faster then lighter ones
8 0
4 years ago
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