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marusya05 [52]
3 years ago
11

If the Moon revolves around the Earth in a circular orbit with a period of 27 days, 7 hours, and 43 minutes, and astronomers hav

e clocked it's orbital speed at 1.03 km/s, what is the centripetal acceleration of the Moon due to its orbit around the Earth?
Physics
1 answer:
inysia [295]3 years ago
6 0

Answer:

T = (27 da * 24 hr/da + 7 hr + 43 min/60 min/hr) * 3600 sec/hr = 2.36 * 10E6 sec       period of moon in sec

C = v t  = 2 pi R        circumference of orbit where v is orbital speed

ac (centripetal acceleration) =  v^2 / R = v^2 / (v t / 2 pi) = 2 pi v / t

ac = 2 pi * 1.03 * 10E3 m/s / 2.36 * 10E6 sec = 2.74 * 10E-3 m /s^2

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Which process is an example of a physical change?
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Answer:

Option A

Carrots are cut into small pieces and mixed into a salad

Explanation:

When physical changes occur, the actual composition remain the same but the molecules are re-arranged. Therefore, when carrots are cut into smaller pieces and mixed into salad, there will be no chemical reaction hence the actual composition will remain the same despite being cut and molecules in it re-arranged. Considering the other options, new substances are formed hence they are deemed as chemical changes. Therefore, option A is correct.

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2 years ago
6. Jim wishes to push a 100. N wood crate across a wood floor.What is the minimum horizontal force that would be required to sta
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I want to say the answer is 42N
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3 years ago
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Vygotsky’s theory of cognitive development states that an individual constructs knowledge primarily through interaction with imp
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3 years ago
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A 0.140-kg baseball is dropped from rest from a height of 1.8 m above the ground. It rebounds to a height of 1.4 m. What change
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Answer:

\Delta p=-1.56\ kg-m/s

Explanation:

It is given that,

Mass of the baseball, m = 0.14 kg

It is dropped form a height of 1.8 m above the ground. Let u is the velocity when it hits the ground. Using the conservation of energy as :

u=\sqrt{2gh}

h = 1.8 m  

u=\sqrt{2\times 9.8\times 1.8}

u = 5.93 m/s

Let v is the speed of the ball when it rebounds. Again using the conservation of energy to find it :

v=\sqrt{2gh'}

h' = 1.4 m  

v=-\sqrt{2\times 9.8\times 1.4}

v = -5.23 m/s

The change in the momentum of the ball is given by :

\Delta p=m(v-u)

\Delta p=0.14(-5.23-5.93)

\Delta p=-1.56\ kg-m/s

So, the change in the ball's momentum occurs when the ball hits the ground is 1.56 kg-m/s. Hence, this is the required solution.

4 0
3 years ago
A bus driver drove from Philadelphia to Washington DC. He drove the first 100km in 2 hours, the next 55km in 1 hour, and the fin
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Answer:

b. 46 km/hr

Explanation:

Applying,

S' = d'/t'................... Equation 1

Where S' = Average speed of the bus, d' = Total distance covered by the bus, t' = Total time taken.

From the question,

d' = (100+55+75) km = 230 km

t' = (2+1+2) = 5 hours

Substitute these values into equation 1

S' = 230/5

S' = 46 km/hr.

Hence the correct option is b. 46 km/hr

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3 years ago
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