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3 years ago

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If the Moon revolves around the Earth in a circular orbit with a period of 27 days, 7 hours, and 43 minutes, and astronomers hav

e clocked it's orbital speed at 1.03 km/s, what is the centripetal acceleration of the Moon due to its orbit around the Earth?

1 answer:

inysia [295]3 years ago

6 0

Answer:

T = (27 da * 24 hr/da + 7 hr + 43 min/60 min/hr) * 3600 sec/hr = 2.36 * 10E6 sec period of moon in sec

C = v t = 2 pi R circumference of orbit where v is orbital speed

ac (centripetal acceleration) = v^2 / R = v^2 / (v t / 2 pi) = 2 pi v / t

ac = 2 pi * 1.03 * 10E3 m/s / 2.36 * 10E6 sec = 2.74 * 10E-3 m /s^2

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A plastic-foam container used as a picnic cooler contains a block of ice at 0°C. If 225g of ice melts, how much heat passes thro

Dima020 [189]

Answer:

18kcal

Explanation:

Melting enthalpy of water: 80 cal/g

The melting enthalpy discribes how much heat is needed to melt a substance. So you get the heat by multiplying the mass of your substance with its melting enthalpy.

225g*18cal/g=18000cal=18kcal

8 0

4 years ago

A fox ﬂeeing from a hunter encounters a 0.700 m tall fence and attempts to jump it. The fox jumps with an initial velocity of 7.

iris [78.8K]

Answer:0.61 m

Explanation:

Given

Initial velocity (u)=7.40 m/s

launch angle $\theta =45^{\circ}$

height of fence=0.7 m

Trajectory of Projectile is given by

$y=x\tan \theta -\frac{gx^2}{2u^2\cos^2\theta }$

For x=2.1 m

$y=2.1\tan (45)-\frac{9.8\times 2.1^2}{2\times 7.4^2\times (\cos 45)^2}$

$y=2.1-0.789$

$y=1.31 m$

At x=2.1 m Y=1.31

therefore Fox clear fence by a margin =1.31-0.7=0.61 m

7 0

3 years ago

Physics Help Please!!!

liq [111]

The answer is the third graph

3 0

3 years ago

Read 2 more answers

A rocket moves upward from rest with an acceleration of 40 m/s2 for 5 seconds. It then runs out of fuel and continues to move up

Snezhnost [94]

Answer:

Maximum height of rocket = 2538.74 m

Explanation:

We have equation of motion s = ut + 0.5 at²

For first 5 seconds

s = 0 x 5 + 0.5 x 40 x 5² = 500 m

Now let us find out time after 5 seconds rocket move upward.

We have the equation of motion v = u + at

After 5 seconds velocity of rocket

v = 0 + 40 x 5 = 200 m/s

After 5 seconds the velocity reduces 9.8m/s per second due to gravity.

Time of flying after 5 seconds

$t=\frac{200}{9.81}=20.38s$

Distance traveled in this 20.38 s

s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m

Maximum height of rocket = 500 +2038.74 = 2538.74 m

6 0

3 years ago

The thermal efficiency of a power cycle operating in a reversible manner is found to be 50%. Assuming that the same 2 thermal re

inna [77]

Answer:

Explanation:

The thermal efficiency of a Power cycle $\eta = \dfrac{Q_H -Q_c}{Q_H}$

where;

$\eta = 50\% = 0.5$

$Q_H = Heat \ flow \ from \ higher \ temperature$

$Q_c = Heat \ flow \ from \ lower \ temperature$

$0.5 = \dfrac{Q_H -Q_c}{Q_H}$

$0.5 Q_H = Q_H - Q_c$ --- (1)

$Q_c = 0.5 Q_H$ ---- (2)

The coefficient of performance is:

$COP_R = \dfrac{Q_c}{Q_H -Q_c}$

let replace the value of $Q_c = 0.5 Q_H$ in the above equation then;

$COP_R = \dfrac{0.5Q_H}{Q_H -0.5 Q_H}$

$COP_R = \dfrac{0.5Q_H}{0.5 Q_H}$

$COP_R = 1$

The

On the other hand, the heat pump

$COP_{HP} = \dfrac{Q_H}{Q_H -Q_c}$

By replacing equation (1) into the above equation; we have:

$COP_{HP} = \dfrac{Q_H}{0.5Q_{H}}$

$COP_{HP} = \dfrac{1}{0.5}$

$COP_{HP} =2$

t

5 0

3 years ago