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Kobotan [32]
3 years ago
10

delivery ladies is Shivam noted at the thundering sound of 6 second after the lightning was seen by him​

Physics
2 answers:
vitfil [10]3 years ago
8 0

Answer:

this is due to difference in speeds of sound and light

Explanation:

light has a speed of 3×10^8 m/s and it is seen at once because it takes negligible time due to very high speed and short distance  that is why as soon as lightning occurs we can see it . since thundering sound travels with speed of sound which is about 330  to 340 m/s in air hence it takes some time as described in question as 6 seconds

Andre45 [30]3 years ago
7 0

Answer:

Explanation:

This is beacause light travel faster than sound

Lightening is light

Thunder is sound

That's why they first lightening and after6sec sound

Thank you

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A gas expands against a constant external pressure of 2.00 atm until its volume has increased from 6.00 to 10.00 L. During this
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Answer:

ΔU = - 310.6 J (negative sign indicates decrease in internal energy)

W = 810.6 J

Explanation:

a.

Using first law of thermodynamics:

Q = ΔU + W

where,

Q = Heat Absorbed = 500 J

ΔU = Change in Internal Energy of Gas = ?

W = Work Done = PΔV =

P = Pressure = 2 atm = 202650 Pa

ΔV = Change in Volume = 10 L - 6 L = 4 L = 0.004 m³

Therefore,

Q = ΔU + PΔV

500 J = ΔU + (202650 Pa)(0.004 m³)

ΔU = 500 J - 810.6 J

<u>ΔU = - 310.6 J (negative sign indicates decrease in internal energy)</u>

<u></u>

b.

The work done can be simply calculated as:

W = PΔV

W = (202650 Pa)(0.004 m³)

<u>W = 810.6 J</u>

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3 years ago
An incident ray of light strikes water at an angle of 30°. The index of refraction of air is 1.0003, and the index of refraction
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Answer: It’s A

Explanation:

22 degrees

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A certain spring has a spring constant k1 = 660 N/m as the spring is stretched from x = 0 to x1 = 35 cm. The spring constant the
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(a) The equation for the work done in stretching the spring from x1 to x2 is ¹/₂K₂Δx².

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<h3>Work done in the spring</h3>

The work done in stretching the spring is calculated as follows;

W = ¹/₂kx²

W(1 to 2) = ¹/₂K₂Δx²

W(1 to 2)  =  ¹/₂(250)(0.65 - 0.35)²

W(1 to 2)  = 11.25 J

W(0  to 3) = ¹/₂k₁x₁² + ¹/₂k₂x₂² + ¹/₂F₃x₃

W(0  to 3) = ¹/₂(660)(0.35)² + ¹/₂(250)(0.65 - 0.35)² + ¹/₂(105)(0.89 - 0.65)

W(0  to 3) = 64.28 J

Learn more about work done here: brainly.com/question/25573309

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Answer:

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