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Elina [12.6K]
3 years ago
9

two objects are connected by a light string that passes over a frictionless pulley as in the figure below, where m1 A) a1=g

B) a1>g
C) a1 D) a1>a2
E) a1
Physics
1 answer:
Shtirlitz [24]3 years ago
5 0
You didn't attach the figure. Your text is incomplete. And you never got around to asking a question. Other than that, we're on it.
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What is the transmitted intensity of light if an additional polarizer is added perpendicular to the first polarizer in the setup
Fantom [35]

Answer:

3) Transmitted intensity of light if unpolarized light passes through a single polarizing filter = 40 W/m²

- Transmitted intensity of light if an additional polarizer is added perpendicular to the first polarizer in the setup described = 7.5 W/m²

Explanation:

Complete Question

3) What is the transmitted intensity of light if unpolarized light passes through a single polarizing filter and the initial intensity is 80 W/m²?

- What is the transmitted intensity of light if an additional polarizer is added perpendicular to the first polarizer in the setup described in Question 3 (the setup)? Show all work in your answer.

The image of this setup attached to this question as obtained from online is attached to this solution.

Solution

3) When unpolarized light passes through a single polarizer, the intensity of the light is cut in half.

Hence, if the initial intensity of unpolarized light is I₀ = 80 W/m²

The intensity of the light rays thay pass through the first single polarizer = I₁ = (I₀/2) = (80/2) = 40 W/m²

- According to Malus' law, the intensity of transmitted light through a polarizer is related to the intensity of the incident light and the angle at which the polarizer is placed with respect to the major axis of the polarizer before the current polarizer of concern.

I₂ = I₁ cos² θ

where

I₂ = intensity of light that passes through the second polarizer = ?

I₁ = Intensity of light from the first polarizer that is incident upon the second polarizer = 40 W/m²

θ = angle between the major axis of the first and second polarizer = 30°

I₂ = 40 (cos² 30°) = 40 (0.8660)² = 30 W/m²

In the same vein, the intensity of light that passes through the third/additional polarizer is related to the intensity of light that passes through the second polarizer and is incident upon this third/additional polarizer through

I₃ = I₂ cos² θ

I₃ = intensity of light that passes through the third/additional polarizer = ?

I₂ = Intensity of light from the second polarizer that is incident upon the third/additional polarizer = 30 W/m²

θ = angle between the major axis of the second and third/additional polarizer = 60° (although, it is 90° with respect to the first polarizer, it is the angle it makes with the major axis of the second polarizer, 60°, that matters)

I₃ = 30 (cos² 60°) = 30 (0.5)² = 7.5 W/m²

Hope this Helps!!!

5 0
3 years ago
What is the initial velocity of the object represented by the graph?
Arturiano [62]

Initial velocity of the object: 5 m/s

Explanation:

The figure in the problem is missing: find it in attachment.

The graph in the figure represents the velocity of an object (v) versus the time passed (t).

Here we are asked to find the initial velocity of the object.

This means that we have to find the velocity of the object when the time is zero, so when

t = 0

By looking at the corresponding value on the y-axis (velocity), we see that when t = 0, then

v = 5 m/s

Therefore, the initial velocity of the object is 5 m/s.

Learn more about velocity:

brainly.com/question/5248528

#LearnwithBrainly

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3 years ago
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I believe that our solar system formed by the same process as star formation. A huge cloud of dust and gas collapsed and condens
Anuta_ua [19.1K]

The correct answer:

nebular theory

The explanation:

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-the Big bang theory is about the origin of the universe

- and condensation theory relates to the formation of the Moon and the Earth.

8 0
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Describe how a wheel and axle work?
andrezito [222]

A weally works when you pull something and a axle is something that you can push

Explanation:

I hope this helps

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What is the purpose of the magnetic field in a cathode ray tube?
andre [41]

Answer:

In order to determine if the cathode ray consisted of charged particles, Thomson used magnets and charged plates to deflect the cathode ray. He observed that cathode rays were deflected by a magnetic field in the same manner as a wire carrying an electric current, which was known to be negatively charged.

Explanation:

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