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3 years ago

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two objects are connected by a light string that passes over a frictionless pulley as in the figure below, where m1 A) a1=g

B) a1>g
C) a1 D) a1>a2
E) a1

1 answer:

Shtirlitz [24]3 years ago

5 0

You didn't attach the figure. Your text is incomplete. And you never got around to asking a question. Other than that, we're on it.

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The magnet below is cut in half. what will be the result?

loris [4]

Answer:

the correct would be c

Explanation:

a magnet will always have a north and a south so if you cut the magnet in half the north part would have a south on the opposite end and vice versa .

3 0

3 years ago

A wheel of radius R = 0.80 m is pulled by a rope looped around a frictionless axle. The total mass of the wheel and axle assembl

iragen [17]

Answer:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

Explanation:

To find the rotational kinetic energy you first calculate the angular acceleration by using the following formula:

$\tau=I\alpha\\\\FR=I\alpha\\\\\alpha=\frac{FR}{I}$

F: force applied

R: radius of the wheel

I: moment of inertia

$\alpha=\frac{(120N)(0.80m)}{26.88kgm^2}=3.57\frac{rad}{s^2}$

With this value you calculate the angular velocity:

$\omega^2=\omega_o^2+2\alpha \theta\\$

you calculate how many radians the wheel run in 5.0m

$\theta=\frac{2\pi (0.8m)}{5.0m}=\approx1.00rad$

$\omega=\sqrt{2(3.57\frac{rad}{s^2})(1.00rad)}=2.67\frac{rad}{s}$

Next, you use the formula for the rotational kinetic energy:

$K_R=\frac{1}{2}I\omega^2=(26.88)(2.67)^2 J = 188.63J$

For the transnational kinetic energy you use the following equation:

$W=\Delta K_T$ (net work equals the change in the kinetic energy).

By replacing the you obtain:

$\Delta K_T=Fd=(120)(5.0)J=600J$

Finally, the ratio between translational rotational kinetic energy is:

$\frac{K_T}{K_R}=\frac{600J}{188.63J}=3.18$

hence, translational kinetic energy is three times the rotational kinetic energy.

6 0

3 years ago

A steel plate has a hole in it with a diameter of exactly 1.0 cm when the plate is at a temperature of 20 degrees C. A steel rin

Dominik [7]

Answer:

c. the hole in the plate and the opening in the ring get larger.

Explanation:

The hole in the plate and the ring both of them get enlarged.

The thermal expansion is very much similar to the optical expansion of the shadow of an object.

<em>The change in length of an object is given by the relation:</em>

$\Delta l=l.\alpha.\Delta T$

where:

l = original length of the object

$\alpha=$ coefficient of linear expansion

ΔT = change in temperature

7 0

3 years ago

if a 3.1g ring is heated using 10.0 calories, its temperatures rises 17.9C calculate the specific heat capacity of the ring

Aleksandr-060686 [28]

So what you do is you use the formula shown below:

specific heat capacity = energy required / (mass * change in temperature)

here ,
energy required = 10.0°C Note that cal. is short form for °C
mass (m) = 3.1g
change in temperature (ΔT) = 17.9°C Note that "ΔT" means change in temperature

So, plugging the values into the formula, we get,

Specific heat capacity= $\frac{10}{3.1*17.9}$

= $0.1802126509$

= 0.1802 cal./g°C <span>i rounded the answer to the fourth decimal point
</span>

6 0

3 years ago

Write down four reasons why plastic is put around electrical wires? <br><br> Plz help me

postnew [5]

Answer:

1) is to prevent accidental contact with other conductors of electricity

2) to prevent getting shocked

3) Plastic helps dissipate the heat as well as prevent the wire from getting too hot and causing fire.

4) Without plastic, hot and neutral wires cannot be run in the same conductor or same wire

Explanation:

hope this helped and plz mark me as brainliest

3 0

3 years ago

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