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3 years ago

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two objects are connected by a light string that passes over a frictionless pulley as in the figure below, where m1 A) a1=g

B) a1>g
C) a1 D) a1>a2
E) a1

1 answer:

Shtirlitz [24]3 years ago

5 0

You didn't attach the figure. Your text is incomplete. And you never got around to asking a question. Other than that, we're on it.

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In an experiment, an object is released from rest from the top of a building. Its speed is measured as it reaches a point that i

NikAS [45]

Answer:

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

Explanation:

As we know that the air friction or resistance due to air is neglected then we can use the equation of kinematics here

$v_f^2 - v_i^2 = 2 a d$

since we released it from rest so we have

$v_i = 0$

so here we have

$v_f = \sqrt{2gd}$

now if the distance is double then we have

$v_f' = \sqrt{2g(2d)}$

now from above two equations we can say that

$v_f' = \sqrt2 v_f$

so the speed will increase by 1.44 times then the initial speed if the distance is increased to double

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3 years ago

What is the force acting on the object?(g=10m/s^2)

Vera_Pavlovna [14]

Answer:w=mxg

2x10 =20 N

Explanation:force acting downwards is mg mass into gravitional feild

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3 years ago

Two loudspeakers placed 8.0 m apart are driven in phase by an audio oscillator whose frequency range is 2.2 kHz to 2.9 kHz. A po

My name is Ann [436]

Answer:

The answer to the question is 2.2khz

Explanation:

<em>Let z₁ = 5.4m</em>

<em>Let z₂ = 4.6m</em>

<em>The path difference Δz = z₁-z₂ = 5.4 - 4.6 = 0.8m</em>

<em>For the interference= Δz λ, 2λ, 3λ......</em>

<em>The wavelength λ = 0.8m</em>

<em>The speed of sound v = 344m/s</em>

<em>The frequency f = v/λ = 344/0.8 = 430hz</em>

<em>Now,</em>

<em>f₁ =f, f₂= 2f, f₃ = 3f, f₄= 4f, f₅ =5f which is,</em>

<em>f₁ =f = 430Hz, f₂=2f =860Hz, f₃ =3f =1290Hz f₄ =4f =1720Hz and f₅=5f =2150Hz</em>

<em>f5 = 2120Hz = 2.200Hz </em>

<em>we will convert to two significant figures =2.2kHz</em>

<em> </em>

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3 years ago

Both X-rays and gamma rays have higher frequencies than ultraviolet rays <br> True or False

mamaluj [8]

Answer:

i believe its True

Explanation:

7 0

3 years ago

Read 2 more answers

On a cross-country trip, a couple drives 500 mi in 10 h on the first day, 380 mi in 8.0 h on the second day, and 600 mi in 15 h

Zepler [3.9K]

We know that the average speed is simply the ratio of the total distance travelled over the total duration of the trip.

total distance = 500 mi + 380 mi + 600 mi

total distance = 1,480 mi

total time = 10 h + 8 h + 15 h

total time = 33 h

So the average speed is therefore:

average speed = 1,480 mi / 33 h

<span>average speed = 44.85 mi / h</span>

8 0

3 years ago