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mihalych1998 [28]
3 years ago
11

#1. What, roughly, is the percent uncertainty in

Physics
1 answer:
miss Akunina [59]3 years ago
6 0

The  uncertainty in the volume measurement of the spherical beach ball is 0.011%.

The given parameters;

the radius measurement , r = 0.846 ± 0.04 m

first radius = 0.846 m

second radius = 0.04 m

The volume of a sphere is given as;

V=\frac{4}{3} \pi r^3\\\\

The volume of the sphere with the measurement ;

V=\frac{4}{3} \pi r^3\\\\V_1 = \frac{4}{3} \pi \times (0.846)^3\\\\V_1 = 2.537 \ m^3

The volume of the sphere with the absolute uncertainty;

V=\frac{4}{3} \pi r^3\\\\V_2 = \frac{4}{3} \pi \times (0.04)^3\\\\V_2 = 0.000268  \ m^3

The uncertainty in the volume measurement is calculated as;

\% \ uncertainty = \frac{absolute \ uncertainty }{measurement} \times 100\%\\\\\% \ uncertainty = \frac{0.000268}{2.537} \times 100\%\\\\\% \ uncertainty = 0.011 \ \%

Thus, the  uncertainty in the volume measurement of the spherical beach ball is 0.011%.

Learn more her: brainly.com/question/12742671

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(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

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t/RC = ln(2)

t = RC x ln(2)

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<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

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t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

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