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mihalych1998 [28]
3 years ago
11

#1. What, roughly, is the percent uncertainty in

Physics
1 answer:
miss Akunina [59]3 years ago
6 0

The  uncertainty in the volume measurement of the spherical beach ball is 0.011%.

The given parameters;

the radius measurement , r = 0.846 ± 0.04 m

first radius = 0.846 m

second radius = 0.04 m

The volume of a sphere is given as;

V=\frac{4}{3} \pi r^3\\\\

The volume of the sphere with the measurement ;

V=\frac{4}{3} \pi r^3\\\\V_1 = \frac{4}{3} \pi \times (0.846)^3\\\\V_1 = 2.537 \ m^3

The volume of the sphere with the absolute uncertainty;

V=\frac{4}{3} \pi r^3\\\\V_2 = \frac{4}{3} \pi \times (0.04)^3\\\\V_2 = 0.000268  \ m^3

The uncertainty in the volume measurement is calculated as;

\% \ uncertainty = \frac{absolute \ uncertainty }{measurement} \times 100\%\\\\\% \ uncertainty = \frac{0.000268}{2.537} \times 100\%\\\\\% \ uncertainty = 0.011 \ \%

Thus, the  uncertainty in the volume measurement of the spherical beach ball is 0.011%.

Learn more her: brainly.com/question/12742671

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Answer: Carbon tetrachloride Or Tetrachloromethane

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On Venus, the acceleration due to gravity is 8.87 m / s 2 . How far would a 17 g rock fall from rest in 6.5 s if the only force
algol [13]

Answer:

187.38 m

Explanation:

Using the equation of motion

s = ut + 1/2gt²...................... Equation 1

Where s = distance of fall, u = initial velocity of the rock, t = time taken for the rock to fall from rest, g = acceleration due to gravity of venus.

Given: u = 0 m/s ( from rest), t = 6.5 s, g = 8.87 m/s².

substituting into equation 1

s = 0(6.5) + 1/2(8.87)(6.5)²

s = 0 + 374.7575/2

s = 187.38 m.

Hence the rock will fall 187.38 m

7 0
3 years ago
Two forces, F? 1 and F? 2, act at a point, as shown in the picture. (Figure 1) F? 1 has a magnitude of 9.20 N and is directed at
Stolb23 [73]

Answer:

a. Fx = -8.089 N b. Fy = 3.525 N c. 8.824 N d. 336.45°

Explanation:

Since F₁ = 9.2 N and acts at 57° above the negative axis in the second quadrant, its x-component is -F₁cos57° and its y- component is F₁sin57°

Since F₁ = 5.2 N and acts at 53.7° below the negative axis in the third quadrant, its x-component is -F₂cos53.7° and its y- component is -F₂sin53.7°

Part A

What is the x component Fx of the resultant force?

The x component of the resultant force Fx = -F₁cos57° + -F₂cos53.7° = -9.2cos57° + (-5.2cos53.7°) = (-5.011 - 3.078) N = -8.089 N

Part B

What is the y component Fy of the resultant force?

The y component Fy of the resultant force = F₁sin57° + -(F₂sin53.7°) = 9.2sin57° - 5.2sin53.7° = (7.716 - 4.191) N = 3.525 N

Part C  

What is the magnitude F of the resultant force?

The magnitude F of the resultant force = √(Fx² + Fy²)

F = √(-8.089² N + 3.525² N) = √65.432 + 12.426 = √77.858 = 8.824 N

Part D

What is the angle ? that the resultant force forms with the negative x axis?

The angle the resultant force makes with the negative x axis is given by

θ = tan⁻¹(Fy/Fx) = tan⁻¹(3.525/-8.089) = tan⁻¹-0.4358 = -23.55°.

To measure it from the negative x axis, we add 360. So, our angle = 360 -23.55 = 336.45°

7 0
3 years ago
HELP PLS i need this right now
N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }

where:

Vx = - 43 units

Vy = 11.1 units

Now replacing:

V=\sqrt{(-43)^{2} +(11.1)^{2} }\\V=44.4 units

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Straight upward

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Projectile motion is the motion of an object thrown (projected) into the air.

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  • A projectile can be a thrown ball, a bullet or a springboard diver ... Except for air resistance, the forward velocity of any projectile is constant and is equal to the initial velocity when it was released.

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