1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marta_Voda [28]
3 years ago
12

Jack has two boxes. One is 148g and one is 78g. If jack pushes both boxes with the same amount of force, which will accelerate f

aster?
A. They will accelerate at the same rate, cause the same amount of force was applied

B. Niethier box wil accelerate

C. THe 148g box

D. The 78g box
Physics
1 answer:
Step2247 [10]3 years ago
8 0
The 78g box, since it has less weight, would accelerate faster. If you had a frictionless surface, and you conducted this experiment, both boxes, without any outside forces, would accelerate at the same rate forever. However, in this problem we must assume the surface is not frictionless. Friction is determined by weight; the more weight, the more friction. Since the 78g box has less weight, it has less friction, making it easier to push with less force.
You might be interested in
In space movies, spacecrafts explode and oxygen is needed for a fire to start. Why is it wrong? What would really happen?
Triss [41]

Answer:

Hey

The reason these "space movies" are wrong is because objects in "space" (not in a "space" craft) can't catch on fire because there is no air in "space".

6 0
3 years ago
A 75-g bullet is fired from a rifle having a barrel 0.540 m long. choose the origin to be at the location where the bullet begin
lyudmila [28]
Part a) The work done by the gas on the bullet is the integral of the force in dx, where x is the distance covered by the bullet inside the barrel with respect to the origin:
W= \int\limits^{0.540m}_{0} {F} \, dx =  \int\limits^{0.540m}_{0} {(16000+10000x-26000x^2)} \, dx =
=16000x+10000  \frac{x^2}{2} - 26000  \frac{x^3}{3}
By substituting the length of the barrel, L=0.540 m, we find the total work done by the gas on the bullet:
W=16000(0.540m)+10000  \frac{(0.540m)^2}{2} - 26000  \frac{(0.540m)^3}{3}  =
=8733 J=8.73 kJ

part b) The resolution of the problem is the same, we just have to use the new length of the barrel (L=0.95 m) inside the final formula, and we find the new value of the work:
W=16000(0.95m)+10000  \frac{(0.95m)^2}{2} - 26000  \frac{(0.95m)^3}{3}  =
=12280 J=12.28 kJ
5 0
3 years ago
An electron in a television tube is accelerated uniformly from rest to a speed of 8.4\times 10^7~\text{m/s}8.4×10 ​7 ​​ m/s over
stich3 [128]

Answer:

P=3.42×10^-6 J/s

Explanation:

From the kinematics of motion with constant acceleration we know that :  

vf^2=vi^2+2*a(xf-xi)

Where :

• vf , vi, are the the final and the initial velocity of the electron  

• a is the acceleration of the electron  

• xf , xi are the final and the initial position of the electron .

Strategy for solving the problem : at first from the given information we calculate the acceleration of the electron.  

Givens: vf = 8.4 x 10^7 m/s , vi, = 0 m/s , xf = 0.025 m and xi = 0 m  

vf^2 =vi^2+2*a(xf-xi)

vf^2-vi^2=2*a(xf-xi)

2*a(xf-xi)= vf^2-vi^2

          a = (vf^2-vi^2)/2(xf-xi)

Pluging known information to get :

a = (vf^2-vi^2)/2(xf-xi)

  = 1.411 × 10^17

From the acceleration and the previous Eq. we can calculate the final velocity of the electron but a new position xf = 0.01 m  

so,

vf^2 =vi^2+2*a(xf-xi)

vf^2 =5.312× 10^7

From the following Eq. we can calculate the time elapsed in this motion .  

xf =xi+vi*t+1/2*a*t

xf =xi+vi*t+1/2*a*t

  t=√2(xf-xi)/a

 t=3.765×10^-10 s

now we can use the power P Eq.  

 P=W/Δt => ΔK/Δt  

Where: the work done W change the kinetic energy K of the electron ,

ΔK=Kf-Ki=>1/2*m*vf^2-1/2*m*vi^2

P=1/2*m*vf^2-1/2*m*vi^2/Δt

P=3.42×10^-6 J/s

6 0
3 years ago
Find the y-component of this
Alborosie

Answer:

-0.0789 m

Explanation:

Recall that the y-component comes associated with the sin(18.4) through the following trigonometric relationship:

y = 0.250 sin(-18.4) ≈ -0.0789 m

Notice it is negative since it is below the x-axis.

4 0
3 years ago
If the sun in 148 million kilometers from the earth, how many minutes will it take the light from the sun to reach the earth?
Natasha2012 [34]

Answer:

about 8 mins and 20 secs

Explanation:

8 0
3 years ago
Other questions:
  • Which three elements have strong magnetic properties?
    11·2 answers
  • Red cabbage juice can be used as an acid-base indicator. When a solution is highly acidic, the juice turns red. As the acidity d
    11·2 answers
  • What is the net force on this object?
    13·2 answers
  • A 4.2 kg parachutist is moving straight downward with a speed of 3.85 m/s
    8·1 answer
  • an object with a mass of 70kilograms is supported at a height 8meters above the ground. what's the potential energy of the objec
    8·1 answer
  • I need help finding the acceleration.
    11·2 answers
  • You lay a rectangular board on the horizontal floor and then tilt the board about one edge until it slopes at angle 0 with the h
    5·1 answer
  • How do we calculate the "range" of the measurements?
    15·1 answer
  • A school is creating a small parking lot next to the school. They will need
    6·1 answer
  • *WILL MARK BRAINLIEST*
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!