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hjlf
3 years ago
13

A heavy object is dropped from a vertical height of 8.0 m. What is its speed when it hits the ground?

Physics
1 answer:
Natali5045456 [20]3 years ago
5 0
What do you know:
d=-8.0mm (starts higher and ends lower so it is negative)
Vi=0m/s (because it was dropped, not thrown)
A=-9.8m/s^2 (gravity)
Vf=???
Use the equation:
Vf^2=Vi^2+2A(d)
Vf^2=2(-9.8)(-8.0)
Vf^2= 156.8 -->find the square root of this
Final answer: Vf= 12.5m/s
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A 3.8 kg ball is rolling eastward across a horizontal,
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4 years ago
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165.529454

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According to the Pythagorean Theorem for calculating the lengths of a right angle triangle's sides, a^2 + b+2 = c^2, where c is the longest side (and the side opposing the right angle). So in your case it would be 150*150 + 70*70 = 27400. And √ 27400 is your answer.

7 0
3 years ago
An owl weighing 40N is sitting in a tree waiting to dive down to catch a mouse. If the owl's potential energy is 800 J with resp
Natali5045456 [20]

Answer:

<em>h = 20 m</em>

Explanation:

<u>Gravitational Potential Energy</u>

Gravitational potential energy (GPE) is the energy stored in an object due to its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or 9.8 m/s^2.

The weight of an object of mass m is:

W = m.g

Thus, the GPE is:

U=W.h

Solving for h:

\displaystyle h=\frac{U}{W}

The weight of the owl is W=40 N and its GPE is U=800 J.

\displaystyle h=\frac{800}{40}=20

h = 20 m

3 0
3 years ago
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