In artificial transmutations the nucleus is bombarded with high-energy (kinetics energy) particles to induce transmutation. There are two reactants or the nucleus that is being bombarded and the high-energy particle.
<span>High-energy particles are accelerated in accelerators, by the application of electric and magnetic fields. Neutrons cannot be accelerated in accelerators using electric and magnetic fields because their charge is 0.
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<u>Answer:</u> The coefficient of carbon in the chemical reaction is 1.
<u>Explanation:</u>
A balanced chemical equation is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.
The chemical equation for the reaction of tin (IV) oxide and carbon follows:
By Stoichiometry of the reaction:
1 mole of tin (IV) oxide reacts with carbon to produce 1 mole of elemental tin and carbon dioxide.
Hence, the coefficient of carbon in the chemical reaction is 1.
1) Chemical reaction
HCl + NaOH ---> NaCl + H2O
25.0 ml
0.150 M 0.250M
2) 50% completion => 0.025 l * 0.150 M * (1/2) = 0.001875 mol HCl consumed and 0.001875 mol HCl in solution
0.001875 mol HCl => 0.001875 mol H(+)
Volume = Volume of HCl solution + Volumen of NaOH solution added
Volume of HCl solution = 0.0250 l
Volume of NaOH = n / M = 0.001875 mol / 0.250M = 0.0075 l
Total volume = 0.0250 l + 0.0075 l = 0.0325 l
[H+] = 0.001875 mol / 0.0325 l = 0.05769 M
pH = - log [H+] = - log (0.05769) = 1.23
Answer: 1.23
3) Equivalence point
0.02500 l * 0.150 M = 0.250M * V
=> V = 0.02500 * 0.150 / 0.250 = 0.015 l
4) 1.00 ml NaOH added beyond the equivalence point
1.00 ml * 1 l / 1000 ml * 0.250 M = 0.00025 mol NaOH in excess
0.00025 mol NaOH = 0.00025 mol OH-
Volume of the solution = 0.02500 l + 0.015 l + 1.00/1000 l = 0.041 l
[OH-] = 0.00025 mol / 0.041 l = 0.00610 M
pOH = - log (0.00610) = 2.21
pH + pOH = 14 => pH = 14 - pOH = 14 - 2.21 = 11.76
Answer: 11.76
Answer:
Only the H is unbalanced.
Explanation:
There are 4 H's and 2 of everything else
Answer:
11.3 g.
Explanation:
Hello there!
In this case, since the combustion of butane is:
Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:
Therefore, the resulting mass of water is:
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