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2 years ago

6. How many electrons will an iodine atom donate or accept, based on its number of valence electrons?

Chemistry

1 answer:

natta225 [31]2 years ago

3 0

Given :

An atom Iodine.

To Find :

How many electrons will an iodine atom donate or accept, based on its number of valence electrons :

A.donate seven electrons

B.accept one electron

C.donate one electron

D.accept seven electrons

Solution :

We know, valence electron in Iodine is 7 electrons.

So, it is easy for iodine to accept 1 electron rather than giving all 7 electrons to another element.

Therefore, Iodine will accept one electron ( Option B.).

Hence, this is the required solution.

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Hellllppppp<br> lons Worksheet

Iteru [2.4K]

The metals will lose electrons while the non metals will gain electrons in order to attain octet structure.

An ion can be cation (positively charged) or anion (negatively charged).

Cations attain octet structure (8) by losing electron(s) while anions become stable or attains octet structure (8) by gaining electron(s).

The remaining elements are completed as follows to attain octet structure;

<u>Element</u>--<u>valence electron</u>--<u>electrons to gain</u>--<u>electrons to lose</u>--<u>ion formed</u>

O ------------ 6 ---------------------- 2 ------------------------ none -------------- $O^{2-}$

Ca -------- 2 ----------------------- none ---------------------- 2 ------------------ $Ca^{2+}$

Br ----------- 7 --------------------- 1 ------------------------ none --------------- $Br^{-}$

S ------------ 6 ----------------------- 2 ------------------------ none --------------- $S^{2-}$

Cl ------------ 7 ----------------------- 1 ------------------------ none ---------------- $Cl^{-}$

K -------------- 1 ----------------------- none ----------------------- 1 ------------------ $K^{+}$

Mg ------------ 2 ---------------------- none ---------------------- 2 ---------------- $Mg^{2+}$

Be ------------- 2 ---------------------- none ---------------------- 2 ---------------- $Be^{2+}$

Learn more here: brainly.com/question/21089350

8 0

2 years ago

How many grams of h2 are needed to produce 14.51 g of nh3?

gavmur [86]

Answer:

2.57 g of H₂

Solution:

The Balance Chemical Equation is as follow,

N₂ + 3 H₂ → 2 NH₃

According to Balance equation,

34.06 g (2 moles) NH₃ is produced by = 6.04 g (3 moles) of H₂

So,

14.51 g of NH₃ will be produced by = X g of H₂

Solving for X,

X = (14.51 g × 6.04 g) ÷ 34.06 g

X = 2.57 g of H₂

7 0

3 years ago

Which solution can turn phenolphthalein pink?

Rasek [7]

I’m pretty sure it’s A sorry if wrong

3 0

3 years ago

Formula D = m / V m = 22 g D = 4 g/mL What is the Volume of the object in mL? Do not include the units in your answer.

Lemur [1.5K]

Answer:

The answer is

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

$volume = \frac{mass}{density} \\$

From the question

mass = 22 g

density = 4 g/mL

The volume is

$volume = \frac{22}{4} = \frac{11}{2} \\$

We have the final answer as

Hope this helps you

6 0

3 years ago

Consider the equation:

Dmitry [639]

Answer:1. $Rate=k[CHCl_3]^1[Cl_2]^\frac{1}{2}$

2. The rate constant (k) for the reaction is $3.50M^\frac{-1}{2}s^{-1}$

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

$rate=k[CHCl_3]^x[Cl_2]^y$