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ki77a [65]
3 years ago
5

Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes th

e moon to orbit the earth. The force of gravitational attraction is represented by the equation F=Gm1m2r2, where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, rrr is the distance between them, and G is the gravitational constant. In SI units, the units of force are kg⋅m/s2, the units of mass are kg, and the units of distance are mm. For this equation to have consistent units, the units of G must be which of the following?
A. kg3m⋅s2
B. kg⋅s2m3
C. m3kg⋅s2
D. mkg⋅s2
Physics
1 answer:
erma4kov [3.2K]3 years ago
7 0

Answer:

C m³/kgs²

Explanation:

From the question, we know that

F = Gm1m2/R², where

F = the Force of gravity in N.

G = gravitational constant, in Nm²/kg²

m1 = mass in kg

m2 = mass in kg

R = distance between the objects in m

Now, if we substitute the units of each in the formula, we have

N = G * (kg * kg) / m²

N = G (kg²) / m²

Nm² = G kg², remember, N itself is kgm/s², so we substitute for that

Kgm/s² * m² = G kg²

Kgm³/s² = G kg²

G = (kgm³/s²) / kg²

G = m³/kgs²

And that's our answer

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A hockey puck is hit on a frozen lake and starts moving with a speed of 13.60 m/s. Exactly 6.2 s later, its speed is 7.20 m/s. (
stellarik [79]

Answer:

-1.03 m/s²

Explanation:

Acceleration: This can be defined as the rate of change of velocity. The S. I unit of acceleration is m/s².

Mathematically, acceleration is expressed as

a = (v-u)/t ........................ Equation 1

Where a = acceleration, v = final velocity, u = initial velocity, t  = time.

Given: u = 13.60 m/s, v = 7.20 m/s t = 6.2 s.

Substituting into equation 2

a = (7.20-13.60)/6.2

a = -6.4/6.2

a = -1.03 m/s²

Note: a is negative because, the hockey puck is decelerating.

Hence the average acceleration = -1.03 m/s²

3 0
3 years ago
if a toaster oven uses 1000 J of electrical energy to produce 800 J of thermal energy, what is the percent efficiency of the toa
ArbitrLikvidat [17]

Answer:

80%

Explanation:

The thermal energy output by the oven is 800 J which is the useful energy that can be utilized for cooking.

The electrical energy input to the oven is 1000 J.

The efficiency of the oven =

(Useful energy output)/(Total energy input to the oven) x 100

=\frac{800}{1000}\times 100= 80\%

Hence, the efficiency of the oven is 80%.

3 0
4 years ago
1) A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3/s. Determine the minimum power that must be sup
azamat

Answer:

\dot{W} = 339.84 W

Explanation:

given data:

flow Q = 9 m^{3}/s

velocity = 8 m/s

density of air = 1.18 kg/m^{3}

minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as

\dot{W} =\dot{m}\frac{V^{2}}{2}

here \dot{m}is mass flow rate and given as

\dot{m} = \rho*Q

\dot{W} =\rho*Q\frac{V^{2}}{2}

Putting all value to get minimum power

\dot{W} =1.18*9*\frac{8^{2}}{2}

\dot{W} = 339.84 W

7 0
3 years ago
Your study buddy claims that an electron always experiences a force in an electric field, but not always in a magnetic field. do
timurjin [86]
It's true charged particles are always acted on by an electric field.when the velocity of the electron is parallel to the magnetic field, the magnetic force vanishes.
4 0
3 years ago
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
3 years ago
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