Velocity is intensive how?

A rabbit trying to escape a fox runs north for 8.0 m, darts northwest for 1.0 m, then drops 1.0 m down a hole into its burrow. W

kifflom [539]

Answer:

9.61 m

Explanation:

d1 = 8 m north

d2 = 1 m north west

d3 = 1 m vertically down

Write the displacements in vector form

$\overrightarrow{d_{1}}=8\widehat{j}m$

$\overrightarrow{d_{2}}=1 \left ( -Cos45\widehat{i}+Sin45\widehat{j} \right )m$

$\overrightarrow{d_{2}}=\left ( -0.707\widehat{i}+0.707\widehat{j} \right )m$

$\overrightarrow{d_{3}}=-1\widehat{k}m$

The resultant displacement is given by

$\overrightarrow{d}=\overrightarrow{d_{1}}+ \overrightarrow{d_{2}} +\overrightarrow{d_{3}}$

$\overrightarrow{d}=-0.707\widehat{i}+ 8.707\widehat{j} - 4\widehat{k}m$

The magnitude of displacement is given by

d =

$\sqrt{\left ( -0.707 \right )^{2}+\left ( 8.707 \right )^{2}+\left ( -4 \right )^{2}}$

d = 9.61 m

4 0

3 years ago

I lift a 20kg ball up 2.5 meters off the ground on Earth.

Umnica [9.8K]

Answer: How much gravitational potential energy does the ball have at this point? At h = 20.4 m the gravitational potential energy of the ball reaches maximum.

How much work did I do lifting up the ball? As you are lifting the object you are doing work on the object. The work W done on an object by a constant force is defined as W = F·d. It is equal to the magnitude of the force, multiplied by the distance the object moves in the direction of the force.

3 0

3 years ago

Youre driving on a straight road (in the +x direction) at a constant speed of 27 m/s. In 10 seconds, you speed up to 34 m/s to p

aleksley [76]

To solve this problem we will apply the concepts related to the kinematic equations of linear motion. For such an effect we will define the average speed, as the distance traveled in the established time.

Our values are given under the following conditions:

$v_i = 27m/s$

$x_1 = v_1 *t$

$x_1 = 27*10 = 270m$

The final distance covered in those 10 seconds at $34 m / s$ would be

$x_2 = 34*10$

$x_2 = 340m$

Therefore the average speed would be the sum of those distances in the total travel time

$v_{Avg} = \frac{340+270}{20}$

$v_{Avg} = 30.5m/s$

Therefore the average velocity is 30.5m/s

6 0

3 years ago

Guys solve question 46...I`ll be very thankful

Cerrena [4.2K]

Answer:

please send the pic again it is not clear

8 0

3 years ago

A beaker of water rests on an electronic balance that reads 875.0 g. A 2.75-cm-diameter solid copper ball attached to a string i

Firdavs [7]

Answer:

a

The tension in the string is $T = 0.85 N$

b

The new balance reading is $M_b = 885.86 g$

Explanation:

From the question we are told that

The mass of the beaker of water is $m = 875 .0g$

The diameter of the copper ball is $d = 2.75 cm = \frac{2.75}{100} = 0.0275 m$

There are two forces acting on the copper ball

The first is the Buoyant force of the water pushing it up which is mathematically represented as

$F = \rho V g$

Where $\rho$ is the density of water which has value of $\rho = 1000 kg/m^3$

g is the acceleration due to gravity $g= 9.8 \ m/s^2$

$V$ is the volume of water displaced by the copper ball which is mathematically evaluated as

$V = \frac{4}{3} \pi r^3$

The radius r is $r = \frac{d}{3} = \frac{0.0275}{2} = 0.01375 m$

Substituting value

$V = \frac{4}{3} * 3.142 * (0.01375)^3$

$V = 1.08 9 *10^{-5 } m^3$

Substituting for F

$F = 1000 * 1.089 *10^{-5} * 9.8$

$F = 0.1067 N$

The second force is the weight of the copper ball which is mathematically represented as

$W_c = mg$

Now m is the mass which can be mathematically evaluated as

$m = \rho_c * V$

Where is the density of copper with value of $\rho_c = 8960 kg /m^3$

So $m = 8960 * 1.089 *10^{-5}$

$m = 0.0976$

So the weight of copper is

$W_c = 0.09756 * 9.8$

$W_c = 0.956 N$

Now the tension the string would be mathematically evaluated as

$T = W_c - F$

So $T = 0.956 - 0.1067$

$T = 0.85 N$

From this value we that the string is holding only 0.85 N of the copper weight thus (0.956 - 0.85 = 0.1065 N ) is being held by the balance

Now the mass equivalent of this weight is mathematically evaluated as

$m_z = \frac{1.0645 }{9.8 }$

$m_z = 0.01086 kg$

Converting to grams

$m_z = 10.86 g$

So the new balance reading is

$M_b = 875.0 +10.86$

$M_b = 885.86 g$

5 0

4 years ago