All categories

3 years ago

An object's buoyant force and weight mean the same thing.A. TrueB. False

Physics

1 answer:

german3 years ago

6 0

Answer:

False

Explanation:

No. The buoyant force on an object is the portion of its weight that appears to vanish

when the object is in any fluid (could be either a liquid or a gas).

If the object happens to float in a particular fluid, then the buoyant force at that moment

is equal to the object's weight.

Notice that the buoyant force on an object will be different in different fluids.

You might be interested in

A 46.5-kg ball has a momentum of 57.2 kg m/s. What is the ball's speed?

Serhud [2]

Answer:

1.23 m/s

Explanation:

p=mv

57.2 = 46.5v

v= 57.2/46.5

v= 1.23

If you want to verify your answer, just insert the value of v in the equation.

5 0

3 years ago

The amplitude of a sound is the A. frequency of the sound. B. magnitude of displacement of a sound pressure wave. C. psychologic

AlladinOne [14]

Answer:

Option B. magnitude of displacement of a sound pressure wave

Explanation:

Amplitude is simply the maximum displacement of a wave from its mean position.

6 0

4 years ago

Read 2 more answers

If a 4500 kg car is traveling with an acceleration of 35.2 m/s/s, what is the force acting on it?

Elena L [17]

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4500 × 35.2 = 158400

We have the final answer as

Hope this helps you

3 0

2 years ago

It is desired to create a particle of mass 7920 MeV/c^2 in a head-on collision between a proton and an antiproton (each having a

Olegator [25]

Answer:

$v=0.9714c$

Explanation:

The kinetic energy possessed by particles will be

$K.E=\frac{1}{2}Mc^2$

where,

M is the mass of the particle (7920938.3 MeV/c²)

c is the speed of the light

Also,

energy of the proton particle = $\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}$

where,

v is the velocity

m_p is the mass of the proton (938.3 MeV/c²)

since the energy is equal

thus,

$\frac{m_pc^2}{\sqrt{1-\frac{v^2}{c^2}}}=\frac{1}{2}Mc^2$

$1-\frac{v^2}{c^2}=[\frac{2m_p}{M}]^2$

substituting the values in the above equation, we get

$1-\frac{v^2}{c^2}=[\frac{2\times 938.3 }{7920}]^2$

$v=0.9714c$

Hence,<u> the speed necessary for the specified condition to occur is </u><u>0.9714 times the speed of the light</u>

5 0

3 years ago

Why does a moving object come to a stop on a frictional surface?

ohaa [14]

It stops cause of gravitaional pull

3 0

4 years ago

An object's buoyant force and weight mean the same thing.A. TrueB. False​

An object's buoyant force and weight mean the same thing.A. TrueB. False