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Dmitry [639]
3 years ago
6

A 40-kilogram crate is at rest on a level surface. If the coefficient of static friction between the crate and the surface is 0.

69, what horizontal force is required to get the crate moving?
Physics
1 answer:
uranmaximum [27]3 years ago
5 0

Answer:

270.8 N

Explanation:

y axis :

N-w=0

N=mg = 40*9.81 =392.4 N

x axis :

P - fs =0

p = meo * N = 0.69 * 392.4 = 270.8 N (ans)

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F_{21} =\frac{Gm_{1}m_{2}}{x_{21}^{2} } is the force that 2 feels because of 1, and

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