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vekshin1
3 years ago
11

What four things are required for photosynthesis?

Physics
1 answer:
drek231 [11]3 years ago
6 0

Explanation:

carbon dioxide, chlorophyll, water and light

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A driver in a car,originally moving 12.2 m/s, applies the brakes until the car comes to a stop. The car moves a distance of 36.5
mojhsa [17]

First we have to calculate the acceleration of the car,

a =\frac{u-v}{t}

Here, u is initial velocity of the car and its value is given 12.2 m/s and v is final velocity of the car and it comes to stop, so its value zero.

a=\frac{0-12.2 m/s}{t} =\frac{-12.2 \ m/s}{t}.

As during the braking the acceleration is constant, from the kinematic equation,

s=ut + \frac{1}{2} a t^2

Here, s is the distance traveled by the car during braking and its value is given 36. 5 m.

Substituting all the values in kinematic equation, we get

36.5 m =(12.2 m/s) t + \frac{1}{2} (- \frac{12.2 m/s}{t}) t^2 \\\\ 36.5 \ m = (12.2 \ m/s) t -(6.1 \ m/s) t \\\\\ t = \frac{36.5 m}{6.1 m/s} = 5.98 s

Therefore, car will stop after 5.98 s.


8 0
3 years ago
The mass of a sports car is 1000 kg. The shape of the car is such that the aerodynamic drag coefficient is 0.260 and the frontal
alisha [4.7K]

Answer:

The initial acceleration is 0,221 m/s^2.

Explanation:

Fcar = Fairfriction\\m*a = 0.5*A*c*density*v^2\\a = 0.5*A*c*density*v^2 / 1000 kg = 0.5*2.10m^2*0.260*1.295kg/m^3*(25 m/s)^2 / 1000 kg = 0,221 m/s^2

8 0
3 years ago
Read 2 more answers
A proton accelerates from rest in a uniform electric field of 680 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativis
Ksivusya [100]

Answer:

Acceleration, a=6.51\times 10^{10}\ m/s^2                                                

Explanation:

Given that,

Electric field, E = 680 N/C

Speed of the proton, v = 1.3 Mm/s

We need to find the acceleration of the proton. We know that the force due to motion is balanced by the electric force as :

qE=ma

a and m are the acceleration and mass of the proton.

a=\dfrac{qE}{m}

a=\dfrac{1.6\times 10^{-19}\times 680}{1.67\times 10^{-27}}

a=6.51\times 10^{10}\ m/s^2

So, the acceleration of the proton is a=6.51\times 10^{10}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
Which of the following statements about iron filings placed upon glass resting on top of a bar magnet is false?
marin [14]

Statements  A,  B,  and  C  are true.

Statement <em> D  is false</em>.

7 0
4 years ago
A 20-cm-long spring is attached to a wall. When pulled horizontally with a force of 100 N, the spring stretches to a length of 2
Delvig [45]

Answer:

the length of stretched spring  in cm is 22

Explanation:

given information:

spring length, x1 = 20 cm = 0.2 m

force, F = 100 N

the length of spring streches, x2 = 22 cm = 0.22 m

According to Hooke's law

F = - kΔx

k = F/*=(x2-x1)

  = 100/(0.22 - 0.20)

  = 5000 N/m

if the spring is now suspended from a hook and a 10.2-kg block is attached to the bottom end

m = 10.2 kg

W = m g

    = 10.2 x 9.8

    = 99.96 N

F = - k Δx

Δx = F / k

     = 99.96 / 5000

     = 0.02

Δx = x2- x1

x2 = Δx + x1

    = 0.20 + 0.02

    = 0.22 m

     = 22 cm

7 0
3 years ago
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