Convection currents in the mantle
Answer:
G=GM/r^2
G=(6.67×10^-11)(6.39×10^23)/(3390000+400000)^2
G=(6.67×10^-11)(6.39×10^23)/(3790000)^2
G=2.967 m/s^2
Explanation:
It passes through C the Electron Cloud
Answer:
22kj
Explanation:
set h = 0 at the end of slide.
final height is -12m
initial condition will be Ui = 0
Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J
Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J
Ki = 1/2mv²
Ki= 1/2 x 61 x (16)² = 7808J
conservation energy says that
Ui + Ki = Uf +Kf +ΔEth
so ΔEth = Ui + Ki - Uf - Kf
ΔEth = 22234.5 - 7808 + 7173
ΔEth = 21600J
ΔEth =22Kj
Explanation:
The pressure on the master piston = the pressure on the slave piston
P₁ = P₂
Pressure is force divided by area:
F₁ / A₁ = F₂ / A₂
Here, F₁ = 20 N, A₁ = 10 cm², and F₂ = 60 N.
(20 N) / (10 cm²) = (60 N) / A₂
A₂ = 30 cm²
