Answer:
Work cause a change in kinetic energy
Answer:
Please find the answer in the explanation
Explanation:
1.) How far is Object Z from the origin at t = 3 seconds
The distance of the object Z from the origin will be the slope of the graph.
Slope = 4/2 = 2m
2.) Which object takes the least time to reach a position 4 meters from the origin ?
According to the graph given to the question above, object Z has the list time which is 2 seconds since object X does not start from the origin.
3.) Which object is farthest from the origin at t = 2 seconds?
The correct answer is still object Z because it has the highest slope.
Answer:
1) Addition of a catalyst
2) To change the reaction rate of slope B to look like slope A, simply add a catalyst to speed up the rate of reaction, giving you a higher amount of products in a shorter amount of time (line A)
Explanation:
1 and 2)Two things can alter the rate of a reaction, either the addition of a catylist which will not alter the composition of the products or reactants, but will accelerate the reaction time, or an increase in temperature will also increase the rate at which a reaction will occur.
You could choose temperature also and have the same result, it's your choice both are correct, but catalyst is the easiest.
Answer:
(a) A = 
(b) 
(c) 
(d) 
Solution:
As per the question:
Radius of atom, r = 1.95
Now,
(a) For a simple cubic lattice, lattice constant A:
A = 2r
A = 
(b) For body centered cubic lattice:


(c) For face centered cubic lattice:


(d) For diamond lattice:


Answer:
The acceleration is equal to the net force divided by the mass. If the net force acting on an object doubles, its acceleration is doubled. If the mass is doubled, then acceleration will be halved. If both the net force and the mass are doubled, the acceleration will be unchanged.