the de Broglie wavelength of the electron moving at a velocity of 3. 0 × 107 m/s is 2.4×10∧-11nm
lambda = h/mv
The de Broglie wavelength is defined as follows: lambda = h/mv, wherein the greek letter lambda represents the wavelength, h is Planck's consistent, m is the particle's mass and v is its pace. One may also explicit mv as the particle's momentum
according to wave-particle duality, the De Broglie wavelength is a wavelength manifested in all the gadgets in quantum mechanics which determines the chance density of locating the item at a given factor of the configuration area. The de Broglie wavelength of a particle is inversely proportional to its momentum
Learn more about de Broglie wavelength here: brainly.com/question/19052579
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Gasoline will not dissolve in water because gasoline has more density then the water
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1) Percent composition
<span>Na: 13.60%,
N: 8.29%
C: 35.51%
H: 4.77%
O: 37.85%
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100.02%
2) Convert mass percent to molar composition
For that, divide the percent of each element by its atomic mass.
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<span>Na: 13.60 / 22.99 = 0.5916
N: 8.29 / 14.01 = 0.5917
C: 35.51 / 12.01 = 2.9567
H: 4.77 / 1.01 = 4.7228
O: 37.85 / 16.00 = 2.3656
3) Divide each number by the smallest one:
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<span><span>Na: 0.5916 / 0.5916 = 1.0
N: 0.5917 / 0.5916 = 1.0
C: 2.9567 / 0.5916 = 5.0
H: 4.7228 / 0.5916 = 8.0
O: 2.3656</span> / 0.5916 = 4.0
4) State the empirical formula: Na N C5 H8 O4
5) Calculate the mass of the empirical formula:
Multiplicate the number of each atoms times the atomic mass corresponding atomic mass of the atom.
1 * 22.99 + 1 * 14.01 + 5 * 12.01 + 8 * 1.01 + 4 * 16.00 = 169.13
6) Divide the molar mass by the mass of the empirical formula:
169 / 169.13 = 1
7) Conclusion: the molecular formula is Na N C5 H8 O4, so the number of atoms present in the compound formula are:
Na: 1
N: 1
C: 5
N: 8
O: 4
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1 molecule of NH3 has 3 atoms of H.
6.90*10²⁴ molecules NH3 have 3*6.90*10²⁴ =20.7*10²⁴ atoms H=2.07*10²⁵ atoms H
1 molecule H2O of has 2 atoms of H.
2.60*10²⁵ molecules of H2O have 2*2.60*10²⁵ =5.20 *10²⁵ atoms of H
2.07*10²⁵ + 5.20 *10²⁵ =7.27*10²⁵ atoms of H altogether.
