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katrin2010 [14]
3 years ago
15

weekly wages at a certain factory are normally distributed with a mean of $400 and a standard deviation of 50. find the probabil

ity that a worker selected at random makes between $300 and $400​
Mathematics
1 answer:
GalinKa [24]3 years ago
3 0

Answer:

47.5%

Step-by-step explanation:

Find the z-scores:

z = (x − μ) / σ

z₁ = (300 − 400) / 50 = -2

z₂ = (400 − 400) / 50 = 0

300 is 2 standard deviations below the mean, and 400 is 0 standard deviations from the mean.

From the empirical rule, 95% of a normal distribution is between -2 and +2 standard deviations.  Since normal distributions are symmetrical, that means half of that is between -2 and 0 standard deviations.

95% / 2 = 47.5%

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Solve the equation and give the solution 6x – 3y = 3 –2x + 6y = 14
fomenos

Answer:

x=3.9 or 39/10 and   y=3.13333 or 47/15

Step-by-step explanation:

Since both expressions (6x-3y) and (3-2x+6y) are equal to 14, separate the equations:

       6x-3y=14 and 3-2x+6y=14

Simplify the equations

       6x-3y=14 and -2x+6y=11

Now, line the equations up and pick a variable (either x or y) to eliminate

        6x-3y=14

        -2x+6y=11

In this case, let's eliminate y first. To do so make the y values in both equations the same but with opposite signs. Make both be 6y but one is +6y and the other -6y

Multiply (6x-3y=14) by 2 to get:

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Line the equations up and add or subtract the terms accordingly

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This becomes:

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Isolate for y

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