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SpyIntel [72]
3 years ago
13

Should you ever grab a tool with expose wiring

Engineering
2 answers:
Stolb23 [73]3 years ago
5 0

Answer: No.

Explanation: It could poke your hand and make you bleed or give you a deathly sickness.

Artyom0805 [142]3 years ago
3 0
No! This is common sense!
You might be interested in
* Write a recursive function that finds the index of s2 in s1. Do not use any * string functions except for .length(), .equals()
ankoles [38]

Answer:

public int indexOfStrings(String s1, String s2) {

if(s1.length() < s2.length())

return -1;

if(s1.substring(0, s2.length()).equals(s2))

return 0;

int index = indexOf(s1.substring(1), s2);

if(index == -1)

return -1;

return 1 + index;

}

Explanation:

First create the method indexOfStrings to receive 2 strings s1 and s2.

Then test with an 'if' statement to check if the length of s1 is less than s2. We hope to find the index s2 in s1 therefore s1 should be greater in length than s2. If this doesn't follow them it should return -1 showing negativity in the function.

Then with check using a substring () function with the endIndex as the length of s2 and beginIndex as 0, to see if the new substring of s1 is equal to string s2. If this true we return 0 and the method ends.

We the initialize index as integer, and repeat the function and insert the substring of s1 with a beginIndex of 1, and the second variable as s2.

We test to see if this index will be equal to -1(negative), if true we end the function.

Finally if all goes well the method returns 1 plus the index integer.

4 0
3 years ago
After having done the hand calculation and pseudocode for a program that models inflating a spherical balloon, now implement the
vampirchik [111]

Answer:

Explanation:

CODE :

import java.util.Scanner; // required imports for the class

class Balloon { // class to run the code

public static void main(String[] args) { // driver method

Scanner in = new Scanner(System.in); // scanner class to get the data

System.out.print("Diameter: "); // message

double diameter = in.nextDouble(); // prompt

double growth = 1; // local variables

int c = 0;

while (c < 10) { // iterate over the loop

double radius = diameter / 2; // calculate the radius

double vol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the initial volume

diameter = growth + diameter; // update the diamter

System.out.printf("\nIncrease in the Diameter is : %.0f", growth); // message

System.out.println("\nNew Diameter is : " + diameter); // print the diameter

radius = diameter / 2; // calculate the new diameter

double growthvol = ((double)4 / 3) * 3.14 * radius * radius * radius; // calculate the new volume

System.out.printf("Increase in the Volume is : %.0f", growthvol - vol); // message

System.out.println("\nNew Volume is : " + growthvol); // message

c++; // increment the count

}

}

}

OUTPUT :

run 1 :

Diameter: 10

Increase in the Diameter is : 1

New Diameter is : 11.0

Increase in the Volume is : 173

New Volume is : 696.5566666666667

Increase in the Diameter is : 1

New Diameter is : 12.0

Increase in the Volume is : 208

New Volume is : 904.3199999999998

Increase in the Diameter is : 1

New Diameter is : 13.0

Increase in the Volume is : 245

New Volume is : 1149.7633333333333

Increase in the Diameter is : 1

New Diameter is : 14.0

Increase in the Volume is : 286

New Volume is : 1436.0266666666666

Increase in the Diameter is : 1

New Diameter is : 15.0

Increase in the Volume is : 330

New Volume is : 1766.25

Increase in the Diameter is : 1

New Diameter is : 16.0

Increase in the Volume is : 377

New Volume is : 2143.5733333333333

Increase in the Diameter is : 1

New Diameter is : 17.0

Increase in the Volume is : 428

New Volume is : 2571.1366666666668

Increase in the Diameter is : 1

New Diameter is : 18.0

Increase in the Volume is : 481

New Volume is : 3052.08

Increase in the Diameter is : 1

New Diameter is : 19.0

Increase in the Volume is : 537

New Volume is : 3589.5433333333335

Increase in the Diameter is : 1

New Diameter is : 20.0

Increase in the Volume is : 597

New Volume is : 4186.666666666667

run 2 :

Diameter: 7.5

Increase in the Diameter is : 1

New Diameter is : 8.5

Increase in the Volume is : 101

New Volume is : 321.39208333333335

Increase in the Diameter is : 1

New Diameter is : 9.5

Increase in the Volume is : 127

New Volume is : 448.6929166666667

Increase in the Diameter is : 1

New Diameter is : 10.5

Increase in the Volume is : 157

New Volume is : 605.82375

Increase in the Diameter is : 1

New Diameter is : 11.5

Increase in the Volume is : 190

New Volume is : 795.9245833333334

Increase in the Diameter is : 1

New Diameter is : 12.5

Increase in the Volume is : 226

New Volume is : 1022.1354166666666

Increase in the Diameter is : 1

New Diameter is : 13.5

Increase in the Volume is : 265

New Volume is : 1287.59625

Increase in the Diameter is : 1

New Diameter is : 14.5

Increase in the Volume is : 308

New Volume is : 1595.4470833333332

Increase in the Diameter is : 1

New Diameter is : 15.5

Increase in the Volume is : 353

New Volume is : 1948.8279166666664

Increase in the Diameter is : 1

New Diameter is : 16.5

Increase in the Volume is : 402

New Volume is : 2350.87875

Increase in the Diameter is : 1

New Diameter is : 17.5

Increase in the Volume is : 454

New Volume is : 2804.7395833333335

Description :

During the casting or the calculation of the volume and the radius the RHS needs to be casted for the numerator with the double datatype so as to clearly get the result. And that the formula is also been updated.

Hope this is helpful.

7 0
4 years ago
Determine the dimensions for W if W = P L^3 / (M V^2) where P is a pressure, L is a length, M is a mass, and V is a velocity.
Eva8 [605]

Correct answer is option E. No dimensions

As we know formula Pressure (P) is \frac{F}{A}

also,

  • Dimensional formula of <em>Pressure is </em>M^{1}L^{-1}T^{-2}
  • Dimensional formula of <em>length is L </em>
  • Dimensional formula of <em>mass is M</em>
  • Dimensional formula  of <em>velocity is </em>L^{1} T^{-1}

So, as given W=\frac{P*L^{3} }{M*V^{2} }

Dimensional formula of W =\frac{M^{1}L^{-1}T^{-2}  L^{3}  }{M^{1} L^{2}T^{-2}   }

since all terms get cancelled

Work is dimensionless i.e no dimensions

Learn more about dimensions here brainly.com/question/20351712

#SPJ10

6 0
2 years ago
Nonshielded cable with a 1.5-inch diameter should have a minimum bending radius of
Flura [38]

Answer:

c is the answer because we have to double the number

6 0
2 years ago
3) The box lands on the surface of the earth.​
OLga [1]
Wait what is the question?
4 0
3 years ago
Read 2 more answers
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