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Akimi4 [234]
3 years ago
5

Drag each label to the correct location on the image.

Engineering
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

The correct classification of characteristics according to the camera model is:

Professional Camera:

has interchangeable lenses

uses charge-coupled devices (CCD)

provides quality videos at a great price is bigger and heavier and may need additional support to carry

Consumer Camera:

provides quality videos at a great price

is mostly automatic

records using tape only

Explanation:

The reasons behind this answer are the following but first of all, we need to say that we are talking about very old cameras. Around 20-year-old gear, so this is very inaccurate to modern cameras. Now, the first reason to classify these matches like we have done it is that in the first place professional cameras that used CCD were really big and required additional supports to be carried, such as tripods, chest munt, or even little cars called dollies. Now we use scorpions and something smaller and lighter. Second, consumer cameras only recorded in tape, back in the day we had no DVD, no memory stick, or even hard drive. The only tape for consumer cameras as the other resources were too expensive to be included on them.

Misha Larkins [42]3 years ago
6 0

The guy above got me this question wrong

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IM JI Suneou uo mm
Oksi-84 [34.3K]

Answer: g

Explanation:

5 0
3 years ago
A surface grinding operation is used to finish a flat plate that is 5.50 in wide and 12.500 in long. The starting thickness is 1
valina [46]

Answer:

77.40

Explanation:

Initial width = 5.5 Inches

Initial length = 12.5 inches

Initial thickness = 1.085 inches

After grinding

Thickness of flat plate  = 1 inch

Grinding wheel

starting diameter( di )= 6.013 inches

width of grinding wheel = 0.5 inch

After operation

Diameter of grinding wheel ( df ) = 5.997

<u>Calculate the grinding ratio in this operation</u>

First step : determine the volume of material removed from flat plate

= Length of flat plate * width of flat plate * change in thickness

= 12.5 * 5.5 * ( 1.085 - 1 )

= 5.8437 in^3

Volume of material from grinding wheel

= π / 4 * ( di^2 - df^2 ) * width  

= π / 4  * ( 6.013^2 - 5.997^2 ) * 0.5

= 0.0755 in^3

<u>Finally the Grinding ratio</u>

= 5.8437  / 0.0755

= 77.4

5 0
3 years ago
Consider 4.8 pounds per minute of water vapor at 100 lbf/in2, 500 oF, and a velocity of 100 ft/s entering a nozzle operating at
andriy [413]

Answer:

A) v_2 = 2016.80 ft/s

B) \Delta s = 0.006 Btu/lbm R  

Explanation:

Given data:

P-1 = 100 lbf/in^2

T_1 = 500 degree f

V_1 = 100 ft/s

P_2 = 40 lbf/inc^2

effeciency = 80%

from steady flow enerfy equation

h_1 +\frac{V_1^2}{2} = h_2 + \frac{V_2^2}{2}

where h1 and h2 are inlet and exit enthalpy

for P1 = 100 lbf/in^2 and T1 = 500 degree F

H_1 = 1278.8 Btu/lbm

s_1 = 1.708 Btu/lbm -R

for P1 = 40 lbf/in^2

H_1 = 1193.5 Btu/lbm

s_1 = 1.708 Btu/lbm -R

exit enthalapy h_2

\eta = \frac{h_1 - h'_2}{ h_1 - h_2}

0.80 = \frac{1278.8 - h'_2}{1278.8 -1193.5} = 1197.77 Btu/lbm

from above equation

1278.8 \times 25037 + \frac{100^2}{2} = 1197.77   \times 25037 + \frac{v_2^2}{2}                   [1 Btu/lbm = 25037 ft^2/s^2]

v_2 = 2016.80 ft/s

b) amount of entropy

\Delta s = s_2 - s_1

s_1 = 1.708 Btu/lbm -R

at h_2 = 1197.77 Btu/lbm [\tex]  and [tex]P_2 = 40 lbf/in^2

s_2 is 1.714 Btu/lbm -R

\Delta s = 1.714 - 1.708 = 0.006 Btu/lbm R

6 0
3 years ago
Buildings designed to partially heat rooms by passive solar heating rely on
Paha777 [63]

Explanation:Image result for buildings designed to partially heat rooms by passive solar heating rely on

A strictly passive design will use the three natural heat transfer modes exclusively—conduction, convection, and radiation. In some applications, however, fans, ducts, and blowers may help with the distribution of heat through the building

4 0
3 years ago
At what depth in water is the increased pressure five times greater than atmospheric pressure (101 kPa)?​
umka21 [38]

Explanation:

40.4m

Explanation:

Pressure at depth is given as

P = P, + pgh

Final pressure at depth h= 5 Po

5Po= Po + pgh

pgh = 4Po = 4 x 1.01 x 10^5

h = (4.04×10^5)/ (1000x10)

h=40.4m

8 0
3 years ago
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