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Akimi4 [234]
3 years ago
5

Drag each label to the correct location on the image.

Engineering
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

The correct classification of characteristics according to the camera model is:

Professional Camera:

has interchangeable lenses

uses charge-coupled devices (CCD)

provides quality videos at a great price is bigger and heavier and may need additional support to carry

Consumer Camera:

provides quality videos at a great price

is mostly automatic

records using tape only

Explanation:

The reasons behind this answer are the following but first of all, we need to say that we are talking about very old cameras. Around 20-year-old gear, so this is very inaccurate to modern cameras. Now, the first reason to classify these matches like we have done it is that in the first place professional cameras that used CCD were really big and required additional supports to be carried, such as tripods, chest munt, or even little cars called dollies. Now we use scorpions and something smaller and lighter. Second, consumer cameras only recorded in tape, back in the day we had no DVD, no memory stick, or even hard drive. The only tape for consumer cameras as the other resources were too expensive to be included on them.

Misha Larkins [42]3 years ago
6 0

The guy above got me this question wrong

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You want a potof water to boil at 105 celcius. How heavy a
ankoles [38]

Answer:

35.7 kg lid we put

Explanation:

given data

temperature = 105 celcius

diameter = 15 cm

Patm = 101 kPa

to find out

How heavy a  lid should you put

solution

we know Psaturated from table for temperature is 105 celcius is

Psat = 120.8 kPa

so

area will be here

area = \frac{\pi }{4} d^2    ..................1

here d is diameter

put the value in equation 1

area = \frac{\pi }{4} 0.15^2

area = 0.01767 m²

so net force is

Fnet = ( Psat - Patm ) × area

Fnet = ( 120.8 - 101 ) × 0.01767

Fnet = 0.3498 KN = 350 N

we know

Fnet = mg

mass = \frac{Fnet}{g}

mass  = \frac{350}{9.8}

mass = 35.7 kg

so 35.7 kg lid we put

3 0
4 years ago
Which of the following is NOT an example of a direct cost of workplace injuries?
hammer [34]

Answer:

Lost productivity

4 0
3 years ago
To increase fault-tolerance, the security administrator for Corp has installed an active/passive firewall cluster where the seco
zheka24 [161]

Answer:

Inbound packets are traversing the active firewall and return traffic is being sent through the passive firewall

Explanation:

5 0
4 years ago
Air (ideal gas) is contained in a cylinder/piston assembly at a pressure of 150 kPa and a temperature of 127°C. Assume that the
Stels [109]

Answer:

The process is not possible.

Explanation:

We know for ideal condition, the work done for isothermal process is

W_{ideal} = P_{1}.V_{1} ln\frac{V_{2}}{V_{1}}

and for ideal gas, we know  PV = mRT

Therefore, W_{ideal} = mRTln\frac{V_{2}}{V_{1}}

                                                  = mRTln\frac{P_{1}}{P_{2}}

                                                  =  0.287 x 400ln\frac{150}{450}

                                                  = -126.12 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 126.12 kJ/kg )

Now we know for adiabatic compression process

                    PV^{\gamma } = C

We know \frac{T_{2}}{T_{1}}=(\frac{P_{2}}{P_{1}})^{\frac{\gamma -1}{\gamma }}

T_{2} = 556 K

For adiabatic work done, W_{adiabatic} = \frac{P_{1}\times V_{1}-P_{2}\times V_{2}}{\gamma -1}

                                                                       = \frac{mR(T_{1}-T_{2})}{\gamma -1}

                                                                       = \frac{0.287(400-556)}{1.45 -1}

                                                                       = -99.49 kJ/kg (negative sign indicates that the process is compressive, so work input to the compressor is 99.49 kJ/kg )

We know that in isothermal process, work input to the compressor is minimum. But in the above adiabatic polytropic process, work input to the compressor is less than the work done in the isothermal process.

Thus the process is not possible.

                                                             

7 0
4 years ago
10 10 10 10 10 10 10 10 10 10
s2008m [1.1K]

Answer:

10

Explanation:

5 0
3 years ago
Read 2 more answers
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