All categories

3 years ago

A remote village on an island was devastated by a typhoon. Farmland was flooded and the crops

Engineering

1 answer:

insens350 [35]3 years ago

6 0

Answer:

A flood happens when water overflows or soaks land that is normally dry. flooding, happens when a large storm or tsunami causes the sea to They soon fell ill and died from cholera, which is spread by Rice, wheat, and corn crops were destroyed. Excess water overflows and runs on top of the land.

Explanation:

hope this helps

You might be interested in

Is a gas turbine a heat engine?

Nookie1986 [14]

Gas turbines extract the energy from combustion gas

and heat engines convert thermal and chemical energy to mechanical energy

gas is considered a chemical so i'm pretty sure it is considered one

4 0

3 years ago

11) 6x^2-49x - 45 What is the factored answer to this trinomial

Lady bird [3.3K]

Factores is (6x+5)(x-9)

3 0

3 years ago

A basketball has a 300-mm outer diameter and a 3-mm wall thickness. Determine the normal stress in the wall when the basketball

faltersainse [42]

Answer:

2.65 MPa

Explanation:

To find the normal stress (σ) in the wall of the basketball we need to use the following equation:

$\sigma = \frac{p*r}{2t}$

Where:

p: is the gage pressure = 108 kPa

r: is the inner radius of the ball

t: is the thickness = 3 mm

Hence, we need to find r, as follows:

$r_{inner} = r_{outer} - t$

$r_{inner} = \frac{d}{2} - t$

Where:

d: is the outer diameter = 300 mm

$r_{inner} = \frac{300 mm}{2} - 3 mm = 147 mm$

Now, we can find the normal stress (σ) in the wall of the basketball:

$\sigma = \frac{p*r}{2t} = \frac{108 kPa*147 mm}{2*3 mm} = 2646 kPa = 2.65 MPa$

Therefore, the normal stress is 2.65 MPa.

I hope it helps you!

3 0

3 years ago

An alloy to be used for a spring application must have a modulus resilience of at least 0.79 x 106 J/m3 (0.79 x 106 Pa). What mu

xxTIMURxx [149]

Answer:

4.13 MPa

Explanation:

Given

Modulus of elasticity = E = 102 GPa

E = 102 * 10^9

Modulus resilience U = 0.79 * 106Pa

Modulus of Resilience U = y²/2E --- Make y the subject of formula

y² = 2EU

y = √(2EU)

y = √(2 * 102 * 10^9 * 0.79 * 106)

y = √1.708296E13

y = 4133153.759540044

y = 4.13E6

y = 4.13MPa

3 0

3 years ago

The structure consists of a very large steel plate they will be used to transfer an in plane tensile stress. You have informatio

SpyIntel [72]

Answer:

$\mathbf{\sigma_{max} =638.308 \ MPa}$

Explanation:

For any large steel plate with an infinite length and width and a center through the crack under tension, the stress intensity factor can be expressed as:

$K_I = \sigma \sqrt{\pi a}$

where;

a = 2.5 mm/2

a = 1.25 mm

a = 1.25 × 10⁻³ m

Therefore; the maximum stress in tension capacity can be computed as;

$\sigma_{max} = \dfrac{K_{I_C}}{\sqrt{\pi a_c}}$

$\sigma_{max} = \dfrac{40}{\sqrt{\pi \times 1.25 \times 10^{-3}}}$

$\mathbf{\sigma_{max} =638.308 \ MPa}$

6 0

3 years ago