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Studentka2010 [4]
4 years ago
12

Please Help I will reward brainliest

Chemistry
1 answer:
Anuta_ua [19.1K]4 years ago
4 0
The answer would be an unpredictable rate
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When [H+] = 3.33 x 10-7 what is the ph?
Fittoniya [83]

Answer:

<h2>6.48 </h2>

Explanation:

The pH of a solution can be found by using the formula

pH = - log ([ {H}^{+} ])

From the question we have

pH =  -  log(3.33 \times  {10}^{ - 7} )  \\  = 6.477555...

We have the final answer as

<h3>6.48 </h3>

Hope this helps you

8 0
3 years ago
A canister of acetylene has a volume of 42 l the temperature of the acetylene is 305 k and the pressure is 780 torr determined t
salantis [7]
PV = nRT

1.026atm * 42l = n * 0.0821L atm/mol K * 305K

n=1.72.

1.72 molecules.
4 0
3 years ago
Fe + CuCl2 → FeCl2 + Cu
inna [77]

Answer:

the type is single replacement

5 0
3 years ago
The columns in the periodic table are also called A. sets. B. periods. C. families. D. energy levels
faust18 [17]
It depends if you are talking about the ones that go up or down
or left and right

the ones that go up and down are called groups

the onesthat go left and right are periods

3 0
3 years ago
Read 2 more answers
For each of the esters provided, identify the alcohol and the carboxylic acid that reacted.
Veronika [31]

Answer:

52. The alcohol USED => methanol, CH3OH

The carboxylic acid USED => propanoic acid, CH3CH2COOH.

53. The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

Explanation:

52. To obtain Methyl propanoate, CH3CH2COOCH3, we simply react propanoic, CH3CH2COOH and methanol, CH3OH together as shown below:

CH3CH2COOH + CH3OH —> CH3CH2COOCH3 + H2O

The alcohol used: methanol, CH3OH

The carboxylic acid used: propanoic acid, CH3CH2COOH.

53. To obtain Ethyl methanoate, HCOOCH2CH3, we simply react

Formic acid, HCOOH and ethanol, CH3CH2OH together as show below:

HCOOH + CH3CH2OH —> HCOOCH2CH3 + H2O

The alcohol USED => Ethanol, CH2CH3OH

The carboxylic acid USED => Formic acid, HCOOH.

7 0
3 years ago
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