Answer:
Work done by the system = 4545 J
Explanation:
The expression for the calculation of work done is shown below as:
Where, P is the pressure
is the change in volume
From the question,
= 45 - 15 L = 30 L
P = 1.5 atm
Also, 1 atmL = 101 J
So,
(negative sign implies work is done by the system)
<u>Work done by the system = 4545 J</u>
Answer:
In order to balance the chemical equation, you need to make sure the number of atoms of each element on the reactants side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal.
Hope this helped you.
Assuming that the number of mols are constant for both conditions:

Now you plug in the given values. V_1 is the unknown.

Separate V_1

V= 162.782608696 L
There are 2 sig figs
V= 160 L