The law of conservation of mass or principle of mass conservation states that for any system closed to all transfers of matter and energy, the mass of the system must remain constant over time, as system mass cannot change quantity if it is not added or removed. Hence, the quantity of mass is "conserved" over time.
Answer:
79.74*10^6 Pa
Explanation:
Based on the parameters provided, we have:
ε = ln()
Where initial gauge length = 3 cm and the final gauge length is 3.5 cm. Therefore:
ε = ln(3.5/3) = ln(1.167) = 0.154
Similarly,
σ = F/[3.142*(di^2)/4]
Where σ = 120*10^6 Pa and di = 1 cm = 0.01 m
Therefore,
F = 120*10^6 * 3.142*(0.01^2)/4 = 9426 N
σ = F/[3.142*(df^2)/4 = 9426/[3.142*(0.00926^2)/4 = 9426/6.74*10^-5 = 139.95*10^6 Pa
σ = k*ε = 139.95*10^6
k = 139.95*10^6/(0.154)^0.5 = 356.63*10^6 Pa
Therefore, when ε = 0.05 cm/cm
σ = 356.63*10^6 (0.05)^0.5 = 79.74*10^6 Pa
Answer: The correct option is A.
Explanation: Chemical reaction is defined as the reaction when there is a formation of new substance. Indicators that help in determining the chemical reaction are:
- Change in Temperature
- Appearance or disappearance of color
- Formation of bubbles
- Formation of a precipitate
- Characteristic odor
Option A: As seen from the image, there is a color change happening in the event. So, it can be considered as a chemical reaction.
Option B: In Event 1, release of heat and light is not visible. Hence, this is not the indicator for detection of chemical reaction.
Option C: In Event 2, we cannot judge the dropping of temperature just by seeing the image. Hence, this cannot be considered as a chemical reaction.
Option D: In this, the color is not mixed throughout the liquid, which means they are not reacting and hence, is not the indicator for chemical reaction.
Therefore, option A is the correct answer.
Absorbance and transmittance are inversely proportional to one another.According to Beer's law a larger amount of light being transmitted through the sample corresponds to a smaller amount of light being absorbed by the sample. <span />