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4 years ago

Which tool would you use to measure the amount of rainfall

2 answers:

8 0

A rain gauge or graduated cylinder is what is used to measure the amount of rainfall!

Hope this helps!
Can u plz mark me as brainliest? I really need it!

mariarad [96]4 years ago

3 0

A rain gauge! Hope this helps!

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A hiker walks 2.00 km north and then 3.00 km east, all in 2.50 hours. Calculate the magnitude and direction of the hiker’s (a) d

tino4ka555 [31]

Answer:

Incomplete third question

I think it should be

C. What was her average speed

Explanation:

Check attachment for solution

5 0

3 years ago

the guage pressure in a car tire is 30.0 psi when the air temperature is 0 C as the day warms up and brighten sun shines What is

Viktor [21]

Answer:

$P_2 = 33.297\ psi$

Explanation:

give,

Gauge pressure of car, P₁ = 30 psi

temperature,T₁ = 0° C = 0 + 273 = 273 K

Assuming temperature at the noon = 30° C

T₂ = 30 + 273 = 303 K

Pressure at this temperature, P₂ = ?

Using ideal gas equation

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

taking volume as in compressible V₁ = V₂

$\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}$

$\dfrac{30}{273}=\dfrac{P_2}{303}$

$P_2 = 303\times \dfrac{30}{273}$

$P_2 = 33.297\ psi$

Hence, Pressure of the at 30°C is equal to 33.297 psi.

3 0

3 years ago

Which statement is true? *

never [62]

The last paragraph is the correct statement. Please don't make me type it all out.

6 0

4 years ago

Read 2 more answers

The vacuum tube was replaced with what electrical component?

Rufina [12.5K]

Answer:

The vacuum tube was replaced with transistor.

Explanation:

The invention of semiconductor was very useful in making solid state transistor that allowed the production of small yet faster, cheaper, and more trusted and reliable computers.
These solid state transistor is so often used that, it nearly replaced all the use of transistor.
This replacement took place after the invention of semiconductor in the year around 1940.
Vacuum tubes also known as thermionic tubes are not used anymore in computers and electronics.

7 0

3 years ago

How much energy, in Joules, is needed to raise the temperature from 25.87°C to 33.16°C in a 2.66 kg block of each of the followi

RUDIKE [14]

Answer:

(a) Silver, H = 455.67 J

(b) Iron, H = 870.67 J

Explanation:

mass of block, m = 2.66 kg = 266 g

T1 = 25.87° C

T2 = 33.16° C

ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C

(a) Specific heat of silver, c = 0.235 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.235 x 7.29 = 455.67 J

(b) Specific heat of iron, c = 0.449 J/g K

The heat required is given by

H = m x c x ΔT

H = 266 x 0.449 x 7.29 = 870.67 J

The heat required is given by

H = m x c x ΔT

H = 266 x 0.522 x 7.29 = 1012.23 J

6 0

3 years ago