1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lianna [129]
3 years ago
11

A 250-kg moose stands in the middle of the railroad tracks in Sweden, frozen by the lights of an oncoming 10,000kg train traveli

ng at 20m/s. Even though the engineer attempted in vain to slow the train down in time to avoid hitting the moose, the moose rides down the remaining track sitting on the train’s cowcatcher. What is the final velocity of the train and moose after the collision?
(Momentum & Impulse)
Physics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

The final velocity of the train and the moose after collision is approximately 19.51 m/s

Explanation:

The given mass of the moose, m₁ = 250 kg

The velocity of the moose, v₁ = 0

The mass of the oncoming train, m₂ = 10,000 kg

The velocity of the train, v₂ = 20 m/s

The velocity of the moose and the train after collision = v₃

By the principle of conservation of linear momentum, the total initial momentum before the collision = The total final momentum after collision

m₁·v₁ + m₂·v₂ = (m₁ + m₂)·v₃

Therefore, by substitution, we have;

250×0 + 10,000× 20 = (10,000 + 250) × v₃

200,000 = 10,250 × v₃

v₃ = 200,000/10,250 ≈ 19.51 m/s

The final velocity of the train and the moose after collision = v₃ ≈ 19.51 m/s

You might be interested in
Are forces of attraction among the particles in all mater? true or false.
Luden [163]

Answer:

the answer is true

Explanation:

3 0
3 years ago
Read 2 more answers
Which statement is the best interpretation of the ray diagram shown below?
Nataly_w [17]

Answer:

A

Explanation:

hope you fell better my answers thanks god bless keep safe and good luck

4 0
3 years ago
Read 2 more answers
Q011) The Doppler effect a. occurs when the frequency of sound waves received is lower if the wave source is moving toward you t
inn [45]

Answer:

Option (c) is correct.

Explanation:

The apparent change in the frequency of light due to the relative motion between the source and the observer is called Doppler's effect.

When the source is moving towards the observer which is at rest, the apparent frequency increases and if the observer is moving away the frequency of sound decreases.

It occurs for both light and sound.  

So, to explain the blue shift of light in the universe is due to the Doppler's effect of light.

8 0
3 years ago
What is the speed of a bobsled whose distance-time graph indicates that it traveled 119m in 29s?
Assoli18 [71]
Do 112m /29s which it will be 3.862 which if you round it, it will be 3.86 m/s
7 0
3 years ago
Read 2 more answers
A young 34-kg ice hockey goalie, originally at rest, catches a 0.145-kg hockey puck slapped at him at a speed of 34.5 m/s. In th
irinina [24]

The concept that we need to give solution to this problem is collision equation given by momentum conservation,

Our values are,

m_2 = 0.145 kg\\u_2 = 34.5 m/s\\m_1 = 34 kg\\u_1 = 0

Then,

Part A) We can here note that the velocity for the puck is zero (there is not a velocity in that direction)

V_{goalie} = \frac{m_1-m_2}{m_1+m_2}V_{01} + \frac{2m_2}{m_1+m_2}V_{02}

V_{goalie} = \frac{34-0.145}{34+0.145}(0)+\frac{2*0.145}{34+0.145}(34.5)

V_{goalie} = 0.2930m/s

Part B ) We apply the same solution but know we note that in the collision for the Goalie the velocity is zero.

V_{puck} = \frac{m_1-m_2}{m_1+m_2}V_{02} + \frac{2m_2}{m_1+m_2}V_{01}

V_{puck} = \frac{34-0.145}{34+0.145}(34.5)+\frac{2*0.145}{34+0.145}(0)

V_{puck} = 34.20m/s

7 0
3 years ago
Other questions:
  • Can someone help me with this whole page? i can't seem to figure it out. Is physics homework
    6·1 answer
  • Cellular phones use _____?
    12·2 answers
  • Help solve these two problems im having trouble trying to start these problems?​
    8·1 answer
  • Choose the scientific notation that best represents the standard notation given. 6,840,000,000 m 68.4 x 108 m 6.84 x 108 m 6.84
    12·2 answers
  • Can someone answer these physics questions
    15·1 answer
  • A ball on the end of a rope is moving in a vertical circle near the surface of the earth. Point A is at the top of the circle; C
    10·1 answer
  • You are growing a little taller each year. What units could you use to measure how fast
    9·2 answers
  • Speed that does not change is known as the:
    9·2 answers
  • Find V. in the circuit of the following figure:​
    9·1 answer
  • Why should you rotate food when thawing it 360 training?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!