9514 1404 393
Answer:
26 square units
Step-by-step explanation:
Counting grid squares on the graph, we see that segment AB is the hypotenuse of a right triangle with legs 2 and 3. Its length is ...
AB = √(2²+3²) = √13
We can also see that the adjacent longer sides are twice this length, each being the hypotenuse of a triangle that is 6 wide and 4 high.
AC = √(6² +4²) = √52 = 2√13
Then the area is ...
A = LW
A = (2√13)(√13) = 2·13 = 26 . . . square units
Answer:
After 1 second, the ball will reach a maximum height of 16 feet
Step-by-step explanation:
The height of the ball after t seconds: h(t) = -16t^2 + 32t
The graph of this quadratic function is parabola which opens downwards. The vertex of a quadratic equation is the maximum or minimum point on the equation's parabola
t = -b/2a = -(32)/2(-16) = -32/-32 = 1 second
then
h(t) = -16(1)^2 + 32(1) = -16 + 32 = 16
After 1 second, the ball will reach a maximum height of 16 feet
Answer:
64°
Step-by-step explanation:
∠RQP = 46°
∠PRQ = 180° - 110° = 70°
∠PRQ + ∠RQP + <u>∠RPQ</u> = 180°
70° + 46 + <u>∠RPQ</u> = 180°
116° + <u>∠RPQ</u> = 180°
Find <u>∠RPQ</u>
<u>∠RPQ</u> = 180° - 116° = 64°
Answer:
C (ignore this it asked for 20 characters)