Answer:
He proposed that matter can be converted to energy and vice versa. He first discovered that nuclear-reaction products are lighter than the reactants. He developed the use of nuclear reactions to generate electricity
Explanation:
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The blades that spin around in the fan, because they are flat and produce work
Answer:
(a) The magnitude of the electric dipole moment is 1.68 x 10⁻¹⁴ C.m
(b) The difference between the potential energies ΔU, is 4.6704 x 10⁻¹¹ J
Explanation:
Given;
magnitude of charge, q = 2 nC = 2 x 10⁻⁹ C
distance of separation, d = 8.4 μm = 8.4 x 10⁻⁶ m
strength of electric field, E = 1390 N/C
(a) the magnitude of the electric dipole moment
p = qd
p = (2 x 10⁻⁹ C)(8.4 x 10⁻⁶ m)
p = 1.68 x 10⁻¹⁴ C.m
(b) the difference between the potential energies for dipole orientations parallel and anti-parallel to E
ΔU = U(180) - U(0)
ΔU = 2pE
ΔU = 2(1.68 x 10⁻¹⁴ )(1390)
ΔU = 4.6704 x 10⁻¹¹ J
Answer:
a. f₀ = 6.355 Hz ; b. Δf = 6.35 Hz
Explanation:
Given Data:
Length of wire = l =347 m ;
Tension in wire = T = 65.2 * 10⁶N ;
Linear density = μ = 3.35 kg/m ;
Solution:
a)
Fundamental mode = f₀ = (1/2l)*(sqr.root(T/μ))
By putting the values, we get
f₀ = (1/2(347))*
f₀ = 6.355 Hz
b)
To find the frequency difference between successive modes we need to find frequency of second harmonic first
f₁ = (2/2l)*(sqr.root(T/μ))
f₁ = (2/2(347))*
f₁ = 12.71 Hz
Difference is:
Δf = f₁ - f₀ = 12.71 - 6.355
= 6.35 Hz
C
Atomic radius is the distance between the center of the nucleus to the outermost orbital shell of the atom. Assume the atom is like a football stadium and the nucleus of the atom is a ball placed at the center of the pitch. The atomic radius is from the center of the ball to the edge of the football stadium.
Explanation:
This atomic radius decreases from left to right of a periodic table because of increases in protons in the nucleus along the periodic table. This increased proton count has a higher attractive force on the electron orbitals of the atom. This decreases the atomic radius
The atomic radius of atoms down a column of the periodic table increase because an extra orbital shell is added to the atoms with every period down the column.
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