3 years ago

HELP ME PLEASE!!!THIS IS SCIENCE!!

1 answer:

4 0

The very first option is correct, as any other answer is either incorrect in terms of optics or does not stop you from seeing the apple.

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A wave with a frequency of 0.5 Hz and a speed of 10 m/s has a wavelength of a. 50 m. c. 20 m. b. 0.5 m. d. 0.2 m.

gladu [14]

We know, wavelength = speed / frequency
w = 10 / 0.5
w = 20 m

In short, Your Answer would be Option C) 20 m

Hope this helps!

5 0

3 years ago

How is a magnetable to pick up bits of metal without actually touching them?

lisov135 [29]

C.There is an invisible magnetic field around the magnet where it exerts magnetic force

7 0

3 years ago

A small car with a mass of 800kg moving with a velocity of 27.8 m/s. The car stops at a yellow light in 3.9 seconds. What force

raketka [301]

Answer:

F = 5702.56 N

Explanation:

Given that,

Mass of a small car, m = 800 kg

Initial speed of the car, u = 27.8 m/s

Final speed, v = 0

Time, t = 3.9 s

We need to find the force did it take for the car to stop.

The force acting on an object is given by :

$F=ma\\\\F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{800\times (0-27.8)}{3.9}\\\\F=-5702.56\ N$

So, the magnitude of force acting on the car to stop is 5702.56 N.

4 0

3 years ago

*PLEASE HELP WILL GIVE BRAINLIEST*

Lorico [155]

More mass will in turn create more force in a collision.

The number of marbles in a collision will affect the outcome because they could bounce off each other and what not.

4 0

3 years ago

A 710 kg car drives at a constant speed of 23 m/s. It is subject to a drag force of 500 N. What power is required from the car's

inn [45]

Explanation:

Given that,

Mass of the car, m = 710 kg

Speed of the car, v = 23 m/s

Drag force, F = 500 N

(a) Let P is the power is required from the car's engine to drive the car on the level ground. Power is given by :

$P=F\times v\\\\P=500\ N\times 23\ m/s\\\\P=11500\ W$

(b) Let P is the power is required from the car's engine to drive the car on up a hill with a slope of 2 degrees.

At this slope, force will be, $F=mg\ \sin\theta$

Total force will be :

$F=710\times 9.8\times \sin(2)+500\\F=742.83\ N$

Power is given by :

$P=F\times v\\\\P=742.83\times 23\\\\P=17085.09\ W$

P = 17 kW

5 0

4 years ago