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barxatty [35]
3 years ago
15

The mountains most commonly found at divergent plate boundaries are

Physics
1 answer:
dybincka [34]3 years ago
8 0
fault-block mountains. hope this helps
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Which statement is true of cooling down after physical activity? A cool-down is a period of semistrenuous activity after physica
Xelga [282]
The statement that is true of cooling down after physical activity is that you should cool down for about 5 to 10 minutes after being physically active.
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3 years ago
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What is the period (in hours) of a satellite circling Mars 100 km above the planet's surface? The mass of Mars is 6.42 × 1023 kg
scZoUnD [109]

To solve this problem it is necessary to apply the concepts related to the Centrifugal Force and the Gravitational Force. Since there is balance on the body these two Forces will be equal, mathematically they can be expressed as

F_c = F_g

\frac{mv^2}{r} = \frac{GmM}{r^2}

Where,

m = Mass

G =Gravitational Universal Constant

M = Mass of the Planet

r = Distance/Radius

Re-arrange to find the velocity we have,

v^2 = \frac{GM}{r}

At the same time we know that the period is equivalent in terms of the linear velocity to,

T = \frac{2\pi}{\frac{v}{r}}

v = \frac{2\pi r}{T}

If our values are that the radius of mars is 3400 km and the distance above the planet is 100km more, i.e, 3500km we have,

v^2 = \frac{GM}{r}

( \frac{2\pi r}{T})^2 =  \frac{GM}{r}

T = \sqrt{\frac{4\pi^2 r^3}{GM}}

Replacing we have,

T = \sqrt{\frac{4\pi^2 (3500*10^3)^3}{(6.67430*10^{-11})(6.42*10^23)}}

T = 6285.09s (\frac{1min}{60s})(\frac{1hour}{60min})

T= 1.74hour

Therefore the correct answer is C.

7 0
3 years ago
The highest speed of a cheetah is 100 km/hr and the highest speed of a gazelle is 80 km/hr. If at t = 0 both animals are running
Tju [1.3M]

Answer:

t=18s

Explanation:

The final position of an object moving at constant speed is given by the formula x=x_0+vt, where x_0 is its initial position, v its speed and t the time elapsed.

For the cheetah we have x_c=x_{0c}+v_ct, and for the gazelle x_g=x_{0g}+v_gt. We want to know at which t their positions are equal, that is, x_c=x_g, which means,

x_{0c}+v_ct=x_{0g}+v_gt

Where we can do:

v_ct-v_gt=x_{0g}-x_{0c}

(v_c-v_g)t=x_{0g}-x_{0c}

t=\frac{x_{0g}-x_{0c}}{v_c-v_g}

We then substitute the values we have (the initial position of the cheetah is 0m), writing the meters in km so distance units cancel out correctly:

t=\frac{0.1km-0km}{100km/hr-80km/hr}=0.005hr=18s

On the last step we just multiply by 3600 because is the number of seconds in an hour.

3 0
3 years ago
A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.0 m/s. The car is a distanc
Brums [2.3K]

For this specific problem, the maximum value for d is 52m. I am hoping that this answer has satisfied your query about and it will be able to help you, and if you’d like, feel free to ask another question.

4 0
2 years ago
A 9-kg object is at rest. Suddenly, it explodes and breaks into two pieces. The mass of one piece is 6 kg and the other is a 3-k
alexandr402 [8]

Answer:

e).

Explanation:

Assuming no external forces acting during the instant of the explosion, total momentum must be conserved.

As the object was initially at rest, the initial momentum is zero, which means that after the explosion, total momentum must add to zero too.

Let's call m₁ = 3 kg-piece and m₂= 6 kg-piece.

⇒ m₁*v₁ + m₂*v₂ = 0

⇒ 3kg* v₁ = -6kg*v₂

⇒ 6/3 = 2 = v₁/v₂ ⇒ v₂/v₁ = 1/2 (in magnitude)

v₂ (being the speed of the 6-kg piece) = 1/2 * v₁ (speed of thr 3-kg piece).

So, we conclude in that  the statement e) is the one that is true.

8 0
3 years ago
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