All categories

3 years ago

The mountains most commonly found at divergent plate boundaries are

Physics

1 answer:

dybincka [34]3 years ago

8 0

fault-block mountains. hope this helps

You might be interested in

Shawn and his bike have a total mass of

Trava [24]

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, $m=52.3\ kg$

Displacement of the bike is, $d=1.6\ km=1.6\times 1000=1600\ m$

Time taken is, $t=17.4\ min=17.4\times 60=1044\ s$

Let the constant velocity be $v$ .

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, $v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s$

Now, kinetic energy of a body is given as:

$KE=\frac{1}{2}mv^2$

Here, $m=52.3\ kg,\ v=1.533\ m/s$

$\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J$

Therefore, Shawn's kinetic energy is 61.45 J.

3 0

3 years ago

A 125kg man buy a 6kg watermelon, a 3kg cantaloupe, and 6kgs of potatoes, he walks home with his purchases in a large bag. His w

Stells [14]

Answer:

350N

Explanation:

Given parameters:

Mass of the man = 125kg

Mass of the watermelon = 6kg

Mass of cantaloupe = 3kg

Mass of potatoes = 6kg

Acceleration = 2.5m/s²

Unknown:

Force required to get home = ?

Solution:

To find this force we use;

Force = mass x acceleration

mass = 125 + 6 + 3 + 6 = 140kg

So;

Net force = 140 x 2.5 = 350N

5 0

3 years ago

A 5.22×104 kg railroad car moves on frictionless horizontal rails until it hits a horizontal spring stopper with a force constan

In-s [12.5K]

To solve this problem we will apply the principles of conservation of energy, for which we have to preserve the initial kinetic energy as elastic potential energy at the end of the movement. If said equality is maintained then we can affirm that,

$\text{Initial Energy}=\text{Final Energy}$

$\frac{1}{2} mv^2=\frac{1}{2} kx^2$

Here,

m = mass

k = Spring constant

x = Displacement

v = Velocity

Rearranging to find the velocity,

$mv^2 = kx^2$

$v^2 = \frac{kx^2}{m}$

$v = \sqrt{\frac{kx^2}{m}}$

Our values are,

$m = 5.22*10^4kg$

$k = 4.58*10^5N/m$

$x = 32cm = 0.32m$

Replacing our values we have,

$v = \sqrt{\frac{(4.58*10^5)(5.22*10^4)}{0.32}}$

$v = 2.733*10^5m/s$

Therefore the velocity is $2.733*10^5m/s$

8 0

4 years ago

.<br><img src="https://tex.z-dn.net/?f=25%20%7B%3F%7D%5E%7B%3F%7D%20%20%5Ctimes%20%5Cfrac%7B%3F%7D%7B%3F%7D%20" id="TexFormula1"

mr_godi [17]

Answer:

what is your exact question.

5 0

3 years ago

Read 2 more answers

Which nucleus completes the following equation?

siniylev [52]

A is the answer I really don’t know the answer to that but if u can u can help me on my work

7 0

3 years ago

Read 2 more answers