Firstly the limiting reactant should be identified. Limiting reactant is the reactant that is in limited supply, the amount of product formed depends on the moles present of the limiting reactant.
the stoichiometry of x to y = 1:2
1 mole of x reacts with 2 moles of y
if x is the limiting reactant, there are 3 moles of x, then 6 moles of y should react, however there are only 4 moles of y. Therefore y is the limiting reactant and x is in excess.
4 moles of y reacts with 2 moles of x
since there are 3 moles of x initially and only 2 moles are used up, excess amount of x is 1 mol thats in excess.
Phenolphthalein turn pink in basic solutions.it turn colourless in acid solution.
Hence options(1)is correct
Answer:
Long answer
Proteins are the building blocks of the body, each and every organ muscle and skin and cells are made of proteins. They can also be used for providing energy to the body in a state where other energy sources aren't available.
Fats are stored energy blocks which can be used by the body at its own convenience whenever there is a deficit of energy in the body. They can also be directly burnt to give energy in cases where energy needs of the body are not met by dietary intake
Carbohydrates are the most convenient and preferable source of energy in the body and are easily converted to give out immidiate energy to the body, excess carbohydrates can be converted into fats and stored for later usage as and when required by the body.
Proteins, fats and carbohydrates have many secondary functions and roles in the human body. If you are keen to know anything more specific feel free to ask.
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Short answer :</h3>
Fats are used for energy after they are broken into fatty acids. Protein can also be used for energy, but the first job is to help with making hormones, muscle, and other proteins.
Explanation:
The given data is as follows.
T =
= (120 + 273.15)K = 393.15 K,
As it is given that it is an equimolar mixture of n-pentane and isopentane.
So,
= 0.5 and
= 0.5
According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.
(393.15 K) = 9.2 bar
(393.15 K) = 10.5 bar
Hence, we will calculate the partial pressure of each component as follows.
![p_{1} = x_{1} \times p^{sat}_{1}](https://tex.z-dn.net/?f=p_%7B1%7D%20%3D%20x_%7B1%7D%20%5Ctimes%20p%5E%7Bsat%7D_%7B1%7D)
= ![0.5 \times 9.2 bar](https://tex.z-dn.net/?f=0.5%20%5Ctimes%209.2%20bar)
= 4.6 bar
and, ![p_{2} = x_{2} \times p^{sat}_{2}](https://tex.z-dn.net/?f=p_%7B2%7D%20%3D%20x_%7B2%7D%20%5Ctimes%20p%5E%7Bsat%7D_%7B2%7D)
= ![0.5 \times 10.5 bar](https://tex.z-dn.net/?f=0.5%20%5Ctimes%2010.5%20bar)
= 5.25 bar
Therefore, the bubble pressure will be as follows.
P =
= 4.6 bar + 5.25 bar
= 9.85 bar
Now, we will calculate the vapor composition as follows.
![y_{1} = \frac{p_{1}}{p}](https://tex.z-dn.net/?f=y_%7B1%7D%20%3D%20%5Cfrac%7Bp_%7B1%7D%7D%7Bp%7D)
= ![\frac{4.6}{9.85}](https://tex.z-dn.net/?f=%5Cfrac%7B4.6%7D%7B9.85%7D)
= 0.467
and, ![y_{2} = \frac{p_{2}}{p}](https://tex.z-dn.net/?f=y_%7B2%7D%20%3D%20%5Cfrac%7Bp_%7B2%7D%7D%7Bp%7D)
= ![\frac{5.25}{9.85}](https://tex.z-dn.net/?f=%5Cfrac%7B5.25%7D%7B9.85%7D)
= 0.527
Calculate the dew point as follows.
= 0.5,
= 0.5
![\frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BP%7D%20%3D%20%5Csum%20%5Cfrac%7By_%7B1%7D%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
![\frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7BP%7D%20%3D%20%5Cfrac%7B0.5%7D%7B9.2%7D%20%2B%20%5Cfrac%7B0.5%7D%7B10.2%7D)
= 0.101966
P = 9.807
Composition of the liquid phase is
and its formula is as follows.
![x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}](https://tex.z-dn.net/?f=x_%7Bi%7D%20%3D%20%5Cfrac%7By_%7Bi%7D%20%5Ctimes%20P%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
= ![\frac{0.5 \times 9.807}{9.2}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5%20%5Ctimes%209.807%7D%7B9.2%7D)
= 0.5329
![x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}](https://tex.z-dn.net/?f=x_%7Bz%7D%20%3D%20%5Cfrac%7By_%7Bi%7D%20%5Ctimes%20P%7D%7Bp%5E%7Bsat%7D_%7B1%7D%7D)
= ![\frac{0.5 \times 9.807}{10.5}](https://tex.z-dn.net/?f=%5Cfrac%7B0.5%20%5Ctimes%209.807%7D%7B10.5%7D)
= 0.467