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3 years ago

One mole of copper equals about how many atoms?

2 answers:

8 0

One mole of copper equals 6.02 × 10^23 atoms. The answer is letter C. This follows the Avogaro’s law wherein 1 mole of a substance is equal to 6.02 x 10^23 atoms, formula units or molecules. This is applicable to all substances.

telo118 [61]3 years ago

6 0

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

According to mole concept:

1 mole of an element or compound contains $6.022\time 10^{23}$ number of particles.

The number is called as Avogadro's number.

We are given:

One mole of a copper element

This element will have the Avogadro's number of particles which is $6.02\times 10^{23}$

Hence, the correct answer is Option c.

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A light source of wavelength, l, illuminates a metal and ejects photoelectrons with a maximum kinetic energy of 1 eV. A second l

madreJ [45]

Explanation:

From first source, kinetic energy ( $K.E_{1}$ ) ejected is 1 eV and wavelength of light is $\lambda$ .

From second source, kinetic energy ( $K.E_{2}$ ) ejected is 4 eV and wavelength of light is $\frac{\lambda}{2}$ .

Relation between work function, wavelength, and kinetic energy is as follows.

K.E = $\frac{hc}{\lambda} - \phi$

where, h = Plank's constant = $6.63 \times 10^{-34}$ J.s

c = speed of light = $3 \times 10^{8}$ m/s

Also, it is known that 1 eV = $1.6 \times 10^{-19}$ J

Therefore, substituting the values in the above formula as follows.

From first source,

$K.E_{1}$ = $\frac{hc}{\lambda} - \phi$

1 eV = $1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda} - \phi$

$1.6 \times 10^{-19} J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (1)

From second source,

$K.E_{2}$ = $\frac{hc}{\lambda} - \phi$

$4 \times 1.6 \times 10^{-19} J = \frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\frac{\lambda}{2}} - \phi$

$6.4 \times 10^{-19} J = \frac{2 \times 1.98 \times 10^{-25} J.m}{\lambda} - \phi$ ........... (2)

Now, divide equation (2) by 2. Therefore, it will become

${6.4 \times 10^{-19}J}{2} = \frac{2 \times 1.98 \times 10^{-25} J.m}{2\lambda} - \frac{\phi}{2}$

$3.2 \times 10^{-19}J = \frac{1.98 \times 10^{-25} J.m}{\lambda} - \frac{\phi}{2}$ ......... (3)

Now, subtract equation (3) from equation (1), we get the following.

$1.6 \times 10^{-19} = \frac{\phi}{2}$

$\phi$ = $3.2 \times 10^{-19}$

= 2 eV

Thus, we can conclude that work function of the metal is 2 eV.

3 0

3 years ago

Which source of energy causes most of the water evaporation on Earth’s surface?

coldgirl [10]

Which adds the most energy to the earth? Solar. So Solar will cause the most evaporation (B)

3 0

3 years ago

Read 2 more answers

1. Intermolecular forces do not have any effect on determining the physical properties of substances such as surface tension and

Scilla [17]

Answer:

1)false

2) false

3)True

4)True

5) false

6)false

7) true

8) d

9)false

10) b

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2 years ago

What is the conversion for 5 g + 3.3 mL =

Dominik [7]

Answer:

9 g/ml

Explanation:

5 + 3.3 = 8.5

But you should use sig figs.

5 has no tenths, hundredths, and etc.

Therefore the 8.5 rounds up to 9

So the answer is 9.

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3 years ago

What volume (L) will 3.56 mol NH3 occupy at STP. (1 point)

mart [117]

Answer:

Explanation:

I hope it helps you good luck

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3 years ago