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3 years ago

One mole of copper equals about how many atoms?

2 answers:

8 0

One mole of copper equals 6.02 × 10^23 atoms. The answer is letter C. This follows the Avogaro’s law wherein 1 mole of a substance is equal to 6.02 x 10^23 atoms, formula units or molecules. This is applicable to all substances.

telo118 [61]3 years ago

6 0

<u>Answer:</u> The correct answer is Option c.

<u>Explanation:</u>

According to mole concept:

1 mole of an element or compound contains $6.022\time 10^{23}$ number of particles.

The number is called as Avogadro's number.

We are given:

One mole of a copper element

This element will have the Avogadro's number of particles which is $6.02\times 10^{23}$

Hence, the correct answer is Option c.

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Question 116 g of sunflower oil is

Luba_88 [7]

<h2>Answer: 125.41 mL</h2>

Explanation:

Volume = mass ÷ density

= 116 g ÷ 0.925 g/mL

= 125.41 mL

<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>

7 0

3 years ago

The volume of a pond being studied for the effects of acid rain is 35 kiloliters (kL). There are 1,000 liters (L) in 1 kL and 1

Lerok [7]

Answer:

35,000,000,000 mL

Explanation:

You first multiply 35 times 1000.

35,000 L

Now you multiply 35,000 times 10^6

35,000,000,000 mL

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3 years ago

A saturated solution of manganese(II) hydroxide was prepared, and an acid–base titration was performed to determine its KspKsp a

trapecia [35]

Answer:

10.945 x 10^-4

Explanation:

Balanced equation:

Mn(OH)2 + 2 HCl --> MnCl2 + H2O

it takes 2 moles HCL for each mole Mn(OH)2

Next find the molarity of the Mn(OH)2 solution

= (1 mole Mn(OH)2 / 2 mole HCl) X (0.0020 mole HCl / 1000ml) X (4.86 ml)

= 4.86 x 10^-3 mole

this is now dissolved in (70 + 4.86) = 74.86 ml or 0.07486 L

thus [Mn(OH)2] = 4.86 x 10^-3 mole / 0.07486 L = 0.064921 M

Ksp = [Mn2+][OH-]^2 = 4x^3 = 4(0.064921)^3 = 10.945 x 10^-4

6 0

3 years ago

In the Haber reaction, patented by German chemist Fritz Haber in 1908, dinitrogen gas combines with dihydrogen gas to produce ga

Reptile [31]

Answer:

The rate at which ammonia is being produced is 0.41 kg/sec.

Explanation:

$N_2+3H_2\rightarrow 2NH_3$ Haber reaction

Volume of dinitrogen consumed in a second = 505 L

Temperature at which reaction is carried out,T= 172°C = 445.15 K

Pressure at which reaction is carried out, P = 0.88 atm

Let the moles of dinitrogen be n.

Using an Ideal gas equation:

$PV=nRT$

$n=\frac{PV}{RT}=\frac{0.88 atm\times 505 L}{0.0821 atm l/mol K\times 445.15 K}=12.1597 mol$

According to reaction , 1 mol of ditnitrogen gas produces 2 moles of ammonia.

Then 12.1597 mol of dinitrogen will produce :

$\frac{2}{1}\times 12.1597 mol=24.3194 mol$ of ammonia

Mass of 24.3194 moles of ammonia =24.3194 mol × 17 g/mol

=413.43 g=0.41343 kg ≈ 0.41 kg

505 L of dinitrogen are consumed in 1 second to produce 0.41 kg of ammonia in 1 second. So the rate at which ammonia is being produced is 0.41 kg/sec.

6 0

3 years ago

A container of gas has a volume of 140.0 cm3 at a temperature of 27.0°C. If the

Vitek1552 [10]

Answer:

285.185 (.185 repeating) cm^3

Explanation:

To get the answer, you divide 140 by 27 to get 5.185 (.185 repeating). Then, you multiply 5.185 (.185 repeating) by 55 and get 285.185 (.185 repeating) cm^3. Please use ^ next time to indicate exponents.

8 0

3 years ago