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n200080 [17]
3 years ago
9

Flammable materials, like alcohol, should never be

Chemistry
1 answer:
jarptica [38.1K]3 years ago
5 0

Answer:

b.open flame because it is fundamental end of the alcohol mixes in with the flame then it will become a bigger fire

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Which laws can be combined to form the ideal gas law? Boyle’s law and Charles’s law Gay-Lussac’s law and Avogadro’s law Charles’
kolezko [41]
Ideal gas law is a combination of three gas laws, which are Boyle's law, Charles' law and Avogadro's law. Ideal gas law states that PV = nRT, where:
P = pressure of the gas
V = volume of the gas
n = no of moles of the gas
R = universal gas constant
T = absolute temperature in Kelvin
7 0
3 years ago
Read 2 more answers
Radiation is spontaneously emitted from hydrogen-3 nuclei, but radiation is not spontaneously emitted from hydrogen-l nuclei or
miv72 [106K]

Answer : Option 1) nuclei of H^{1} and nuclei of H^{2} only.


Explanation : Radiation is spontaneously emitted from nuclei of H^{3} because this isotope of hydrogen is highly radioactive as compared to other isotopes of hydrogen namely; nuclei of H^{1} and nuclei of H^{2}.


They have much stable nucleus as compared to nuclei of H^{3}.


The more it is unstable the more radiations will be emitted from its nucleus.

5 0
3 years ago
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A cube of tin that is 112 mm on each side has a mass of 8.21 grams. A single tin atom has a mass of 118.7 amu. How many tin atom
Sveta_85 [38]

Answer:

4.17e+22 atoms of tin are present in the cube

Explanation:

We don't require the size of the cube. With the mass and the molar mass of tin = 118.7 amu we can find moles of Tin. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:

<em>Moles Tin:</em>

8.21g * (1mol / 118.7g) = 0.0692 moles Tin

<em>Atoms Tin:</em>

0.0692 moles Tin * (6.022x10²³ atoms / mol) =

<h3>4.17e+22 atoms of tin are present in the cube</h3>
5 0
2 years ago
Which of the following hypotheses cannot be tested using the scientific method
Arturiano [62]
I believe it's answer #3. Logically, at least.

You can test #1 through trial and error.
You can experiment #2 also through trial and error.
You cannot test #3 through trial and error, because that would be catastrophic.
You can test #4 through a survey and individual study and data collection.
7 0
3 years ago
Read 2 more answers
Radioactive radium has a half-life of approximately 1,599 years. The initial quantity is 13 grams. How much (in grams) remains a
Luda [366]

The quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

<h3>What is half life period? </h3>

The time taken by substance to reduce to its half of its initial concentration is called half life period.

We will use the half- life equation N(t)

N e^{(-0.693t) /t½}

Where,

N is the initial sample

t½ is the half life time period of the substance

t2 is the time in years.

N(t) is the reminder quantity after t years .

Given

N = 13g

t = 350 years

t½ = 1599 years

By substituting all the value, we get

N(t) = 13e^(0.693 × 50) / (1599)

= 13e^(- 0.368386)

= 13 × 0.691

= 8.98

Thus, we calculated that the quantity of substance remains after 850 years is 8.98g if the half life of radioactive radium is 1,599 years.

learn more about half life period:

brainly.com/question/20309144

#SPJ4

4 0
1 year ago
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