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padilas [110]
2 years ago
10

State the number of complex roots, the number of positive real roots and the number of negative real roots of

Mathematics
1 answer:
harkovskaia [24]2 years ago
8 0

9514 1404 393

Answer:

  • 2 complex roots
  • 2 positive real roots
  • 0 negative real roots

Step-by-step explanation:

The signs of the terms are + - - +. There are two sign changes, so 0 or 2 positive real roots.

Negating the signs of the odd-degree terms, the signs are + + + +. There are no sign changes, so 0 negative real roots.

For x=0, the value of the quartic is +3. For x=1, the value is -3, so we know there are 2 positive real roots, one of which lies in the interval (0, 1).

The 4th-degree polynomial equation must have 4 roots, so the other two must be complex.

  • 2 complex roots
  • 2 positive real roots
  • 0 negative real roots

_____

The roots are approximately 0.489999841592, 2.06573034434, −0.777865092969 ± 1.53582061225i

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Step-by-step explanation:

It can work well to identify 4th powers under the radical, then remove them.

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The constant factors simplify in the usual way:

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