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lions [1.4K]
3 years ago
11

If the pOH of vinegar is 9.45, what is its OH

Chemistry
2 answers:
Nadusha1986 [10]3 years ago
7 0

Answer:

[OH⁻] = 3.55×10⁻¹⁰M

Explanation:

Given data:

pOH of vinegar = 9.45

[OH]  = ?

Solution:

Formula:

pOH = -log[OH⁻]

Now we will put the value of pOH.

9.45 = -log[OH⁻]

[OH⁻] = 10∧-pOH

[OH⁻] = 10⁻⁹°⁴⁵

[OH⁻] = 3.55×10⁻¹⁰M

olganol [36]3 years ago
3 0

Answer:

the answer is 3.55 and -10

Explanation:

hope this helps!

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