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Schach [20]
3 years ago
6

Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?

Chemistry
2 answers:
Kitty [74]3 years ago
8 0

The element that is more likely to form a covalent bonds is silicon (si)

Silicon looks like brown powder in random form; it also looks like a silver-gray metallic-looking when it’s in crystalline form.

<h2>Further Explanation</h2>

Silicon is regarded as a semi-conductor, which implies that it possesses electronic conductivity between conductor and insulator while its conductivity rises with temperature. With all these properties, silicon is considered to be a very important element in electronics.

Silicon has four valence electrons which can form a covalent bonds by sharing its electrons. Also, when in its solid form, silicon doesn’t react with water or oxygen because it is an inert element.

However, a covalent bonds is also known as a molecular bond. It refers to a chemical link involving two atoms in which there is a sharing of electron between them. The electrons shared between the two atoms is called bonding pairs.

Some of the interaction involves covalent bonding include:

  • Metal to metal bonding
  • Bent bonds
  • Agnostic interaction

Covalent bonding can also be found in some chemical species, for example, macromolecules and radicals.

However, there are two types of covalent bonds and they include

  • Polar
  • Nonpolar

Therefore, the element that is most likely to form a covalent bonds is silicon (Si)

LEARN MORE:

  • The element sulfur (S) is most likely to form covalent bonds with the element  brainly.com/question/2177882
  • Which of these pairs of elements is most likely form covalent bonds?  brainly.com/question/3850422

KEYWORDS:

  • silicon
  • covalent bonds
  • polar
  • nonpolar
  • element
kari74 [83]3 years ago
4 0
<span>Answer: K because it is metal and typically forms ionic bonds. Ar is also unlikely to form any bonds because it has a full outer shell of electrons, but it can form covalent bonds.</span>
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A 14.4-gg sample of granite initially at 86.0 ∘C∘C is immersed into 24.0 gg of water initially at 25.0 ∘C∘C. What is the final t
kari74 [83]

Answer:

The final temperature of both substances when they reach thermal equilibrium is 31.2 °C

Explanation:

Step 1: Data given

Mass of sample granite = 14.4 grams

Initial temperature = 86.0 °C

Mass of water = 24.0 grams

The initial temperature of water = 25.0 °C

The specific heat of water = 4.18 J/g°C

The specific heat of granite = 0.790 J/g°C

Step 2: Calculate the final temperature

Heat lost = heat gained

Qgranite = - Qwater

Q = m*c*ΔT

m(granite)*c(granite)*ΔT(granite) = -m(water)*c(water)*ΔT(water)

⇒with m(granite) = the mass of granite = 14.4 grams

⇒with c(granite) = The specific heat of granite = 0.790 J/g°C

⇒with ΔT⇒(granite) = the change of temperature of granite = T2 - T1 = T2 - 86.0 °C

⇒with m(water) = the mass of water = 24.0 grams

⇒with c(water) = The specific heat of water = 4.18 J/g°C

⇒with ΔT(water) = the change of temperature of granite = T2 - T1 = T2 -25.0°C

14.4 grams * 0.790 * (T2 - 86.0°C) = -24.0 *4.18 * (T2 - 25.0°C)

11.376T2 - 978.336 = -100.32T2 + 2508

111.696 T2 = 3486.336

T2 = 31.2 °C

The final temperature of both substances when they reach thermal equilibrium is 31.2 °C

4 0
3 years ago
A solution of Cuso, is labelled 1.743 M. How much Cuso, in grams, must be used to make
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Answer:

Option A. 416.1 g.

Explanation:

Data obtained from the question include the following:

Molarity = 1.743 M

Volume = 1.4957 L

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Next, we shall determine mole of CuSO4 present in the solution.

This is illustrated below:

Molarity is simply defined as the mole of solute per unit litre of the solution. Mathematically, it is expressed as:

Molarity = mole /Volume

With the above formula, we can obtain the mole CuSO4 present in the solution as follow:

Molarity = 1.743 M

Volume = 1.4957 L

Mole of CuSO4 =..?

Molarity = mole /Volume

1.743 = mole of CuSO4 /1.4957

Cross multiply

Mole of CuSO4 = 1.743 x 1.4957

Mole of CuSO4 = 2.607 moles

Finally, we shall convert 2.607 moles of CuSO4 to grams.

This can be obtained as follow:

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Mole of CuSO4 = 2.607 moles

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Mole = mass /molar mass

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Cross multiply

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Mass of CuSO4 = 416.1 g

Therefore, 416.1 g of CuSO4 is needed to prepare the solution.

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