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Schach [20]
3 years ago
6

Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?

Chemistry
2 answers:
Kitty [74]3 years ago
8 0

The element that is more likely to form a covalent bonds is silicon (si)

Silicon looks like brown powder in random form; it also looks like a silver-gray metallic-looking when it’s in crystalline form.

<h2>Further Explanation</h2>

Silicon is regarded as a semi-conductor, which implies that it possesses electronic conductivity between conductor and insulator while its conductivity rises with temperature. With all these properties, silicon is considered to be a very important element in electronics.

Silicon has four valence electrons which can form a covalent bonds by sharing its electrons. Also, when in its solid form, silicon doesn’t react with water or oxygen because it is an inert element.

However, a covalent bonds is also known as a molecular bond. It refers to a chemical link involving two atoms in which there is a sharing of electron between them. The electrons shared between the two atoms is called bonding pairs.

Some of the interaction involves covalent bonding include:

  • Metal to metal bonding
  • Bent bonds
  • Agnostic interaction

Covalent bonding can also be found in some chemical species, for example, macromolecules and radicals.

However, there are two types of covalent bonds and they include

  • Polar
  • Nonpolar

Therefore, the element that is most likely to form a covalent bonds is silicon (Si)

LEARN MORE:

  • The element sulfur (S) is most likely to form covalent bonds with the element  brainly.com/question/2177882
  • Which of these pairs of elements is most likely form covalent bonds?  brainly.com/question/3850422

KEYWORDS:

  • silicon
  • covalent bonds
  • polar
  • nonpolar
  • element
kari74 [83]3 years ago
4 0
<span>Answer: K because it is metal and typically forms ionic bonds. Ar is also unlikely to form any bonds because it has a full outer shell of electrons, but it can form covalent bonds.</span>
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Read 2 more answers
An unknown compound is processed using elemental analysis and found to contain 117.4g of platinum 28.91 carbon and 33.71g nitrog
dlinn [17]

Answer:

1 mole of platinum

Explanation:

To obtain the number of mole(s) of platinum present, we need to determine the empirical formula for the compound.

The empirical formula for the compound can be obtained as follow:

Platinum (Pt) = 117.4 g

Carbon (C) = 28.91 g

Nitrogen (N) = 33.71 g

Divide by their molar mass

Pt = 117.4 / 195 = 0.602

C = 28.91 / 12 = 2.409

N = 33.71 / 14 = 2.408

Divide by the smallest

Pt = 0.602 / 0.602 = 1

C = 2.409 / 0.602 = 4

N = 2.408 / 0.602 = 4

The empirical formula for the compound is PtC₄N₄ => Pt(CN)₄

From the formula of the compound (i.e Pt(CN)₄), we can see clearly that the compound contains 1 mole of platinum.

8 0
3 years ago
How many moles of glucose are in 19.1g of glucose?​
Crank

Answer:

0.106 mol (3s.f.)

Explanation:

To find the number of moles, divide the mass of glucose (in grams) by its Mr. Glucose has a chemical formula of C6H12O6. To find the Mr, add all the Ar of all the atoms in C6H12O6.

Ar of C= 12, Ar of H= 1, Mr of O= 16

These Ar values can be found on the periodic table.

Mr of glucose= 6(12)+ 12(1) + 6(16)= 180

Moles of glucose

= mass ÷ mr

= 19.1 ÷ 180

= 0.106 mol (3 s.f.)

3 0
3 years ago
Here is a more complex redox reaction involving the dichromate ion in acidic solution: 3N O 2 − + 8H + + C r 2 O 7 2− → 3N O 3 −
Fantom [35]

Answer:

NO2- is the reducing agent.

Cr2O7_2- is the oxidizing agent.

H+ is neither

Explanation:

Reduction is the gain in electron. A chemical specie that undergoes reduction is called the oxidizing agent.

Oxidation is simply the loss in electrons. A chemical specie that undergoes oxidation is called the reducing agent.

Let us look at the species.

The first specie is the NO2-. In this specie, the oxidation number of nitrogen changed from +3 to +5 in NO3-. Thus we can see that there is more loss of electron to have caused an increase in the oxidation number positively. This shows an oxidation. Hence, NO2- is the reducing agent.

Let us look at the chromium. We can see that the oxidation number of chromium changed from +7 to +3.

Now we can see that it is a decrease and hence, it is a gain of electron and thus it is reduction. This means the first chromium specie is the oxidizing agent.

The hydrogen ion is simply placed there to balance the ions and hence it is neither the oxidizing nor the reducing agent.

4 0
4 years ago
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