Answer:
look at the picture above
Which substance is the reducing agent in this reaction? 2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH
2 answers:
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Answer:
0.12 mL of the epinephrine solution.
Explanation:
We have:
A bottle of epinephrine labeled 1 mg in 1 mL of solution,
We need to prepare:
An injection of 0.12 mg of epinephrine
Hence:
Therefore, to prepare an injection of 0.12 mg of epinephrine labeled 1 mg in 1 mL we need to inject 0.12 mL of the epinephrine solution.
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