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nikdorinn [45]
2 years ago
8

Which substance is the reducing agent in this reaction? 2KMnO4+3Na2SO3+H2O→2MnO2+3Na2SO4+2KOH

Chemistry
2 answers:
olganol [36]2 years ago
6 0
I believe <span>Na2SO3  is the solution to the problem.</span>
viva [34]2 years ago
6 0
The reducing agent would be the substance that is oxidized in the reaction or the one who loses electrons. From the reaction given, it would be KMnO4 that is  the reducing agent. It loses electrons From (MnO4)2- to MnO2. Hope this answers the question.
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2 years ago
When FeC13 is ignited in an atmosphere of pure oxygen, this reaction takes place. 4FeCl3(sJ 30lgJ ~ 2F~0 (sJ 6Cl2(gJ If 3.00 mol
oksano4ka [1.4K]

Answer : The reagent present in excess and remains unreacted is, O_2

Solution : Given,

Moles of FeCl_3 = 3.00 mole

Moles of O_2 = 2.00 mole

Excess reagent : It is defined as the reactants not completely used up in the reaction.

Limiting reagent : It is defined as the reactants completely used up in the reaction.

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

2FeCl_3(s)+O_2(g)\rightarrow 2FeO(s)+3Cl_2(g)

From the balanced reaction we conclude that

As, 2 moles of FeCl_3 react with 1 mole of O_2

So, 3.00 moles of FeCl_3 react with \frac{3.00}{2}=1.5 moles of O_2

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4 0
2 years ago
In a 63.17 g sample of SO3, how many grams are sulfur?
Evgesh-ka [11]

Answer:

25.30 gram

Explanation:

No of moles = given mass / molar mass

No of moles = 63.17/80.06

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Mass of sulphur = 0.7890×32.065

25.30 gram

4 0
2 years ago
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