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kkurt [141]
3 years ago
11

What is the main reason why many nuclear power plants are located near bodies of water? to wash wastes out of the power plant to

be close to shipping lanes for frequent fuel delivery to have easy access to a coolant for the reactor to avoid problems with water supply during a drought
Physics
2 answers:
Natalija [7]3 years ago
7 0

Answer: to avoid problems with water supply

Explanation: power plant needs water to run

marta [7]3 years ago
4 0

Answer:

the answer is "C."

Explanation:

they need water to cool down.

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A solid object has a mass of 104 kg and a volume of 1,278 m3. What is its density? 0.081 kg/m3 12.29 g/cm3 132912.00 g/cm3 canno
REY [17]
The density is 81.4 g/m3. Before you start plugging numbers into the density formula (D=M/V), you should convert 104 kg to grams, which ends up being 104,000 grams. Then you can plug in the 104,000 grams and 1,278 m3 into the formula. When you divide the mass by the volume, you get a really long decimal, which you can round to 81.4 g/m3, or whatever place your teacher wants you to round to.
4 0
3 years ago
Read 2 more answers
1. A student practicing for a track meet ran 263 m in 30 sec. What was her average speed?
faltersainse [42]

Answer: By 47

Explanation: subtract 310 and 263

6 0
2 years ago
Estimate the force required to bind the two protons in the He nucleus together. (Hint: Model the protons as point charges. Assum
scoray [572]

Answer:

 F = 2.30 10⁴ N

Explanation:

The force required to link two gates must be equal to or greater than the electrostatic force of repulsion, because the protons have equal charges.

                 F = k q₁ q₂ / r²

Where k is the Coulomb constant that is worth 8.99 10⁹ N m² / C²

   In this case the proton charge is 1.6 10⁻¹⁹ C and the distance between them is approximately the diameter of the core r = 10⁻¹⁵ m

Let's calculate

              F = 8.99 10⁹ (1.6 10⁻¹⁹)² / (10⁻¹⁵)²

              F = 2.30 10⁴ N

The bond strength must be equal to or greater than this value

3 0
3 years ago
Which law states that the pressure and absolute temperature of a fixed quantity of gas are directly proportional under constant
Brrunno [24]

<u>Gay Lussac’s law</u> state that the pressure and absolute temperature of a fixed quantity of a gas are directly proportional under constant volume conditions.  

<h2>Further Explanation </h2><h3>Gay-Lussac’s law  </h3>
  • It states that at constant volume, the pressure of an ideal gas I directly proportional to its absolute temperature.
  • Thus, an increase in pressure of an ideal gas at constant volume will result to an increase in the absolute temperature.
<h3>Boyles’s law   </h3>
  • This gas law states that the volume of a fixed mass of a gas is inversely proportional to its pressure at constant absolute temperature.
  • Therefore, when the volume of an ideal gas is increased at constant temperature then the pressure of the gas will also increase.
<h3>Charles’s law </h3>
  • It states that the volume of a fixed mass of a gas is directly proportional to absolute temperature at constant pressure.
  • Therefore, an increase in volume of an ideal gas causes a corresponding increase in its absolute temperature and vice versa while the pressure is held constant.
<h3>Dalton’s law  </h3>
  • It is also known as the Dalton’s law of partial pressure. It states that the total pressure of a mixture of gases is always equivalent to the total sum of the partial pressures of individual component gases.
  • Partial pressure refers to the pressure of an individual gas if it occupies the same volume as the mixture of gases.

Keywords: Gas law, Gay-Lussac’s law, pressure, volume, absolute temperature, ideal gas

<h3>Learn more about: </h3>
  1. Gay-Lussac’s law: brainly.com/question/2644981
  2. Charles’s law: brainly.com/question/5016068
  3. Boyles’s law: brainly.com/question/5016068
  4. Dalton’s law: brainly.com/question/6491675

Level: High school  

Subject: Chemistry  

Topic: Gas laws  

Sub-topic: Gay-Lussac’s law  

8 0
3 years ago
Read 2 more answers
Review Conceptual Example 6 as background for this problem. A car is traveling to the left, which is the negative direction. The
DiKsa [7]

Answer:

(a) 1.21 m/s² (b) 1.75 m/s²

Explanation:

The initial speed of the car, u = 17.8 m/s

Case 1.

Final speed of the car, v = 23.5 m/s

Time, t = 4.68-s

Acceleration = rate of change of velocity

a=\dfrac{23.5 -17.8 }{4.68}\\\\a=1.21\ m/s^2

Case 2.

Final speed of the car, v = 15.3 m/s

a=\dfrac{23.5 -15.3}{4.68}\\\\a=1.75\ m/s^2

Hence, this is the required solution.

3 0
2 years ago
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