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Zolol [24]
2 years ago
8

A student wants to determine the speed of sound at an elevation of one mile. To do this the student performs an experiment to de

termine the resonance frequencies of a tube that is closed at one end. The student takes measurements every day for a week and gets different results on different days. Which of the following experiments would help the student determine the reason for the different results?
a. Repeating the experiment on several 10 degree C days and several 20 degree C days
b. Repeating the experiment using a wider range of frequencies of sound
c. Repeating the original experiment for an additional week
d. Repeating the experiment using a longer tube
Physics
1 answer:
Lorico [155]2 years ago
3 0

Answer:

The correct answer is a

Explanation:

The speed of a sound wave depends on the square root of the modulus of compressibility and the density of the medium.

For the same medium, the speed of sound depends on the temperature of the fora

           v = v_o \ \sqrt{1 + \frac{T}{273} }

Therefore, the different results that are obtained are due to changes in temperature. The correct answer is a

since this way it has the values ​​of the speed of sound for each temperature, for which it can compare with the results obtained from the trip.

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Dentify the following terms associated with the water cycle.
vivado [14]

Answer:

condensation, precipitation, evaporation, transpiration

Explanation:

condensation is when gas condenses into liquid, precipitation is when water comes from the sky like in rain, evaporation is when water is converted from liquid to gas, transpiration is when water is evaporated from leaves.

4 0
2 years ago
A rigid tank initially contains 3kg of carbon dioxide (CO2) at a pressure of 3bar.The tank is connected by a valve to a friction
marissa [1.9K]

Answer:

Part a: <em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b: <em>The total amount of energy transfer by the heat is 54.81 kJ</em>

Explanation:

Mass of Carbon Dioxide is given as m1=3 kg

Pressure is given as P1=3 bar =300 kPA

Volume is given as V1=0.5 m^3

Pressure in tank 2 is given as P2=2 bar=200 kPa

T=290 K

Now the Molecular weight of CO_2 is given as

M=44 kg/kmol

the gas constant is given as

R=\frac{\bar{R}}{M}\\R=\frac{8.314}{44}\\R=0.189 kJ/kg.K

Volume of the tank is given as

V=\frac{mRT}{P_1}\\V=\frac{3 \times 0.189 \times 290}{300 }\\V=0.5481 m^3

Final mass is given as

m_2=\frac{P_2V}{RT}\\m_2=\frac{200\times 0.5481}{0.189\times 290}\\m_2=2 kg

Mass of the CO2 moved to the cylinder

m=m_1-m_3\\m=3-2=1 kg

The initial mass in the cylinder is given as

m_{(cyl)_1}=\frac{P_{(cyl)_1}V_1}{RT}\\m_{(cyl)_1}=\frac{200\times 0.5}{0.189 \times 290}\\m_{(cyl)_1}=1.82 kg

The mass after the process is

m_{(cyl)_2}=m_{(cyl)_1}+m\\m_{(cyl)_2}=1.82+1\\m_{(cyl)_2}=2.82\\

Now the volume 2 of the cylinder is given as

V_{(cyl)_2}=\frac{m_{(cyl)_2}RT}{P_2}\\m_{(cyl)_2}=\frac{2.82\times 0.189\times 290}{200}\\m_{(cyl)_1}=0.774 m^3

Part a:

So the Work done is given as

W=P(V_2-V_1)\\W=200(0.774-0.5)\\W=54.81 kJ

<em>The total amount of energy transfer by the work done is 54.81 kJ.</em>

Part b:

The total energy transfer by heat is given as

Q=\Delta U+W\\Q=0+W\\Q=54.81 kJ

As the temperature is constant thus change in internal energy is 0.

<em>The total amount of energy transfer by the heat is 54.81 kJ</em>

7 0
3 years ago
what type of motion occurs when an object spins around an axis without alternating its linear position
Zolol [24]
Rotational motion occurs when an object spins around an axis without alternating its linear position.


hope this helped :)
4 0
2 years ago
A cylindrical tube sustains standing waves at the following frequencies: 600 Hz, 800 Hz, and 1000 Hz. The tube does not sustain
Thepotemich [5.8K]

Answer:

Explanation:

In  closed organ pipe notes with odd harmonics are produced and in open organ pipe notes with all odd and even harmonics are produced. notes with frequencies 600, 800 and 1000 Hz are produced. These are 3 , 4 and 5 times 200 Hz. ie both odd and even times of 200 . So fundamental frequency appears to be 200 Hz. There is no note available between 800 and 1000. It also indicates that 200 Hz is the fundamental frequency and the pipe is open at both ends.

3 0
3 years ago
Calcium-51 has a half-life of 4.5 days. Only 0.75 gram remains of a sample that was initially 12 grams. How old is the sample of
Over [174]
How many times did the original sample lose 50% of its radioactivity ?

-- Start with. . . . . . . . . . . . 12 grams.
-- Lose half of it once. . . . . . 6 grams left.
-- Lose half of it again . . . . . 3 grams left.
-- Lose half of it again . . . . . 1.5 grams left.
-- Lose half of it again . . . . . 0.75 gram left.

-- How many times did it lose half ?    4 times.

-- How long does it take to lose half ?  4.5 days. 
                                                       (That's why it's called the 'half-life'.)

-- How long did it take to lose half, 4 times ?

                                           (4 x 4.5 days) = 18 days .
6 0
3 years ago
Read 2 more answers
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