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Zolol [24]
2 years ago
8

A student wants to determine the speed of sound at an elevation of one mile. To do this the student performs an experiment to de

termine the resonance frequencies of a tube that is closed at one end. The student takes measurements every day for a week and gets different results on different days. Which of the following experiments would help the student determine the reason for the different results?
a. Repeating the experiment on several 10 degree C days and several 20 degree C days
b. Repeating the experiment using a wider range of frequencies of sound
c. Repeating the original experiment for an additional week
d. Repeating the experiment using a longer tube
Physics
1 answer:
Lorico [155]2 years ago
3 0

Answer:

The correct answer is a

Explanation:

The speed of a sound wave depends on the square root of the modulus of compressibility and the density of the medium.

For the same medium, the speed of sound depends on the temperature of the fora

           v = v_o \ \sqrt{1 + \frac{T}{273} }

Therefore, the different results that are obtained are due to changes in temperature. The correct answer is a

since this way it has the values ​​of the speed of sound for each temperature, for which it can compare with the results obtained from the trip.

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Korolek [52]
Both ve similar equations 
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7 0
3 years ago
A conducting rod (length = 2.0 m) spins at a constant rate of 2.0 revolutions per second about an axis that is perpendicular to
vladimir2022 [97]

Answer:

0.050V

Explanation:

To solve this problem it is necessary to use the concepts related to the potential between two objects that have a magnetic field, this concept is represented in the equation.

\int dV = \int_{0}^{l/2} Bv (dl)

Where,

v= tangencial velocity

B = Magnetic Field

We know for definition that,

v= l\omega

Where,

L = length

\omega = Angular velocity

We can replace this values in our first equation then,

\int dV = \int_{0}^{l/2} B (l\omega) (dl)

Integrating we have,

V = \frac{1}{8} Bl^2 \omega

Replacing the values,

V= \frac{1}{8} (8*10^{-3})(12.56)(4)

V = 0.050V

Therefore the potential difference between the  center of the rod and the other rod is 0.050V

7 0
3 years ago
A car is accelerating to the right. In which direction is the applied force?
Natasha_Volkova [10]

Answer:

Left

Explanation:

The force is applied opposite of the acceleration.

8 0
3 years ago
Do transistors amplfy a.c or d.c<br>​
Gnoma [55]

Explanation:

thet amplify DC, because of the voltage ( small current input signal)

5 0
3 years ago
Read 2 more answers
What force is described as the attraction between a sample of matter and all other matter in the universe?
Vinil7 [7]

Answer:

Gravitational Force

Explanation:

Gravitational force also called gravity or gravitation is an attractive force that keeps two objects in space. Gravitational force is an attractive force that tends to pull matters together. Every objects in the universe experience gravitational pull.  Planets, stars, galaxies, are held together by gravity. It is a weak force. The weight of an object is the product of gravitational force acting on its mass.

Newton's Law of Universal Gravitation states the force of attraction between two masses m₁ and m₂ in the universe is directly proportional to the product of their masses and inversely proportional to the square of their distance apart.

                                 F = G\frac{m_{1}m_{2}}{r^2}

Where;

F is the gravitational force,

G is the gravitational constant = 6.67 × 10¹¹ m³/kg/s,

m1 and m2 are the masses of the objects,

r is the distance between the centers of the masses

4 0
3 years ago
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