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Vedmedyk [2.9K]
3 years ago
8

A 15.0 Kg object is moved from a height of 7.00 m above thefloor to a height of 13.0 m above the floor. What is the change ingra

vitational potential energy?
Physics
1 answer:
Pie3 years ago
4 0

To solve this problem we will apply the concepts related to potential gravitational energy. This is defined as the product between mass, acceleration and change in height and can be expressed as,

\Delta PE = mg \Delta h

Here,

m = Mass

g = Gravitational acceleration

\Delta h = Height

Replacing with our values we have,

\Delta PE = (15kg)(9.81m/s^2)(13m-7m)

\Delta PE = 882.9J \approx 883J

Therefore the change in gravitational potential energy is 883J.

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Explanation:

Given that,

Force, F=((-8i)+6j)\ N

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Taking the cross product of above two vectors, we get the value of torque as :

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cos\theta=\dfrac{(3i+4j).((-8i)+6j)}{(\sqrt{3^2+4^2} ).(\sqrt{8^2+6^2}) }

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3 years ago
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<span>C. surface tension of the water.</span>
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While spinning in a centrifuge a 70.0 KG astronaut experiences an acceleration of 2.00g, or twice the acceleration due to gravit
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<em>Thus, the answer is B.</em>
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